If you would like to solve the system of equations, you can do this using the following steps:
4x^2 + 9y^2 = 72
2x - y = 4 ... 2x - 4 = y
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<span>4x^2 + 9y^2 = 72
</span><span>4x^2 + 9 * (2x - 4)^2 = 72
</span>4x^2 + 9 * (4x^2 - 16x + 16) = 72
4x^2 + 36x^2 - 144x + 144 = 72
40x^2 - 144x + 144 - 72 = 0
40x^2 - 144x + 72 = 0
10x^2 - 36x + 18 = 0
5x^2 - 18x + 9 = 0
(5x - 3) * (x - 3) = 0
1. 5x - 3 = 0 ... 5x = 3 ... x = 3/5
2. x = 3
<span>1. y = 2x - 4 = 2 * 3/5 - 4 = 6/5 - 20/5 = -14/5
2. y = 2x - 4 = 2 * 3 - 4 = 6 - 4 = 2
1. (x, y) = (3/5, -14/5)
2. (x, y) = (3, 2)
The correct result would be </span>(3/5, -14/5) and <span>(3, 2).</span>
Answer:
let me think
Step-by-step explanation:
i want free points
Answer:
m < 1 = 18°
Step-by-step explanation:
If <ABD = 72°, and m < 2 is three times the measure of m < 1, then:
Let < ABC = m < 1 = x
< CBD = m < 2 = 3x
We can set up the following formula, since the sum of the measures of angles < 1 and < 2 is equal to <ABD (72°):
m < 1 + m < 2 = < ABD
x + 3x = 72°
Add like terms:
4x = 72°
Divide both sides by 4 to solve for x:
x = 18
Since x = 18, and m < 1 = x , then m < 1 = 18°.
And since m < 2 = 3x, then m < 2 = 3(18°) = 54°.
Let's check to see whether we derived the correct answers by plugging in the values of m < 1 and m < 2 into the established formula:
m < 1 + m < 2 = < ABD
18° + 54° = 72°
72° = 72° (True statement).
Please mark my answers as the Brainliest if my explanations were helpful :)
Answer:
51°
Step-by-step explanation:
Given
<QPR = 39°
<PQR = 90° ( inscribed angle in semi circle)
Now
<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)
39° + 90° + <PRQ = 180°
<PRQ = 180° - 39° - 90°
<PRQ = 51°
Hope it will help :)
