D both are right triangles
Answer:
y = 3
Step-by-step explanation:
-7 = -4y + 5
Subtract 5 from both sides to isolate variable y:
-7 - 5 = -4y + 5 - 5
-12 = -4y + 0
-12 = -4y
Divide both sides by -4 to isolate variable y:
-12 ÷ -4 = -4y ÷ -4
(Negative ÷ Negative = Positive)
3 = 1y
3 = y
Check your work:
-7 = -4(3) + 5
Use PEMDAS:
-7 = -12 + 5
-7 = -7
Correct!
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
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B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)