The value of (k ○ r) (x) from the given parameters in the task content is; 5 ln(2x³ -14)
<h3>What is (k ○ r) (x) from the task content?</h3>
If follows from the task content that;
- r(x) = x³ - 7 and k(x) = 5 ln (2x)
It therefore follows that;
(k ○ r) (x) = k(r(x)) = 5 ln (2(x³-7)).
On this note, the expression which represents (k ○ r) (x) is; 5 ln(2x³ -14).
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Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
Answer:
6 millimeters.
Step-by-step explanation:
1 millimeter : 4 metres
x millimeters : 24 metres
x = (24÷4) × 1
x = 6 × 1
x = 6 millimeters
1500-125=1,375
so 1375 should be your answer.
