Find the period of the function y= 2/3 cos(4/7^x) + 2
2 answers:
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Answer:
<em>Graph included as picture</em>
Step-by-step explanation:
To solve this, plot the given points on the graph
Draw a line through them.
Now select two of those values and we'll find the rate of change.
We'll be using (1,-1) and (3,3)
To find rate of change we will be using the formula:
So the rate of change is 2
You will use this rate of change for your other function because they both have the same rate of change
Since we have the rate of change, we can create the slope intercept form formula: y = mx +b
Just substitute for the variables we know
m = rate of change/slope = 2
b = y-intercept = -3
y = 2x + -3
<em>[If you connected all the points in your graph, that's how you found the y-intercept]</em>
Now we have to create the formula for the second function.
We know it will have that same slope of 2
so we have y = 2x + b
To solve for b we can plug in the values we do have which would be (x,y) of (3,6)
6 = 2(3) + b
Now solve
6 = 6 + b
6 (-6) = 6 (-6) + b
0 = b
b = 0
This mean that the y-intercept will be on (0,0)
Plot that point
Now we finish the formula
y = 2x + 0
Connect the dots, make sure the line continues on both of them past the dots and now you have your graph!
I've included a picture of the graph for your reference. I hope this helps, don't be afraid to reach out with further questions!
