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3 years ago

Find the period of the function y= 2/3 cos(4/7^x) + 2

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

T = 2 π / | 4/7 |

T = 2 π / 4/7

T = 2 π × 7 / 4

T = 7 π / 2

Thus the correct answer is option A .

Svetach [21]3 years ago

3 0

Answer:

The option is A

Step-by-step explanation:

T = 2 π / | 4/7 |

T = 2 π / 4/7

T = 2 π × 7 / 4

T = 7 π / 2

Hope this answer helps you :)

Have a great day

Mark brainliest

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If angle 1 and angle 7 are vertical angles and angle 1 and angle 2 are supplementary adjacent and the measure of angle 2 is 123

JulsSmile [24]

Answer: m∡7 = 57° .
_________________________________

Explanation:
____________________
m∡7 = m∡1 ; SInce these angles are vertical; and vertical angles are congruent.

m∡1 + m∡2 = 180 ; since these angles are supplementary; and by definition; supplementary angles "add up" to 180.

Given: m∡2 = 123 ;

m∡1 + 123 = 180 ;

Since m∡1 = m∡7 ; and we wish to find: "m∡7" ; we can rewrite as:
_______________________________
m∡7 + 123 = 180 ; solve for "m∡7" ;
_______________________________
Subtract "123" from EACH SIDE of the equation:
_________________________________________
m∡7 + 123 - 123 = 180 - 123 ;
_________________________________________
m∡7 = 57° .
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7 0

3 years ago

ITS FOR A TESTT I NEED THE ANSWER

ehidna [41]

Answer:

I believe the answer is $1.52. hope this helps

6 0

2 years ago

A speed limit of 100 kilometers per hour is approximately equal to 62mph. write an equation relating kilometers per hour to mile

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

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4 0

2 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

6 0

3 years ago

What is an equation of the line that passes through the points (4,1) and (8,-3)?

Rus_ich [418]

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

so (-3-1)/(8-4)

-4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so 1=-1(4)+b

1=-4+b

1+4=b

so b= 5

therefore the equation is y=-x+5 so d

8 0

3 years ago