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3 years ago

For which equation is (4, 3) a solution?

Mathematics

2 answers:

Pani-rosa [81]3 years ago

8 0

You will have to put it in point slope from

making it y-3=2 (x-4)

y= 2x - 5

so it would be 3.

PilotLPTM [1.2K]3 years ago

8 0

Answer:

y = 2x – 5 is the right answer

Step-by-step explanation:

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Given the system of equations, what is the value of the system determinant? 2x + y = 8 x - y = 10

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New term for me - system determinant ??

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3 years ago

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15 x 3 - 21/3 divided by 24/4?

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I’m pretty sure it’s 43.8

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Gnoma [55]

Answer: Third option.

Step-by-step explanation:

These are some transformations for a function f(x):

If $f(x)-k$ , then the function is shifted down "k" units.

If $f(x-k)$ , then the function is shifted right "k" units.

Knowing this we can describe the transformation from the graph of the function $f(x) = x^2$ to the graph of the function $f(x) = (x - 3)^2-1$ . This is:

The function $f(x) = (x - 3)^2-1$ is the function $f(x) = x^2$ but shifted right 3 units and shifted down 1 units.

Therefore, the correct option is the third one.

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4 years ago

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Find the max value of c=5x+4y

Zigmanuir [339]

You should be able to find the maximum value of c by simply substituting the maximum values for x and y.

So we'll let x = -2 and y = 6.

The equation is is now as follows:

c = 5(-2) + 4(6)

c = -10 + 24

c = 14

Therefore the maximum value for c is 14.

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3 years ago

(-1,2p³q)(10p²r²)=<br> Help me

MaRussiya [10]

For this case we have the following expression:
$(-1.2p^3q)(10p^2r^2)$
When making multiplication, the first thing you should keep in mind is the following property:
Same basis, the exponents are added.
We have then:
$-12p^{3+2}r^2q$
Rewriting we have:
$-12p^{5}r^2q$
Answer:
The simplified expression is given by:
$-12p^{5}r^2q$

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4 years ago