1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
suter [353]
4 years ago
10

For the pair of functions f and g determine the domain of f o g

Mathematics
1 answer:
skelet666 [1.2K]4 years ago
8 0
When taking the composite of two functions, the resulting domain is the more restrictive of the two original domains. g(x) has a domain of all real numbers, but f(x) has a domain of x=/= 2. So, the domain of f(g(x)) is x=/= 2
You might be interested in
PLSSS HELPPP DUE SOON ILL GIVE BRAINLESS
Kitty [74]

Answer:

D

Step-by-step explanation:

A, B, and C are not linear functions

D would be y=x/2

If you graphed y=x/2, you would get the points (4, 2), (7, 3.5), (8, 4), and (10, 5)

It's more obvious if you notice that y is half of x.

3 0
3 years ago
Find the slope of the line that passes through the pair of points. <br> F(–6, 8), P(–6, –5)
asambeis [7]

-5-8 ÷ -6--6

-13 ÷ 6

gradient = -13/6

6 0
4 years ago
What is the exact volume of the cylinder? Cylinder with height of 6 inches and radius of 3 inches. 324π in3 18π in3 36π in3 54π
Afina-wow [57]
Volume of a cylinder is pi*r^2*h where r = radius and h = height
so 3^2*6*pi = 9*6*pi = 54pi

54 pi is the answer. mark me brainliest please!
8 0
3 years ago
Read 2 more answers
If g(x) is the inverse of f(x), what is the value of f(g(2))?
Elan Coil [88]

Answer:

2

Step-by-step explanation:

So to figure this out we just need to flip the values of x and y in the table and then redefine that as the function g(x), because an inverse is essentially the reverse!

So if we flipped x and y's for f(x). We would see that our output or y of g(x) is -3 when x = 2, or in other words g(2) = -3. This means that we are now going to solve for when f(-3). So now lets look at the table and find the value at x = -3 for f(x). This value is 2, so the value of f(g(2)) = 2.

*In the future*

When you have a composite function of two inverses they essentially cancel out and would leave whatever the value of x is. So if we know f(x) and g(x) were inverses the value of f(g(2)) would just be 2.

For example:

ln(x) and e^x are inverses so if I had a composition like this:

e^{ln(2)}

The answer to this would be 2 because these inverse functions "'cancel" out

So

e^{ln2} = 2

8 0
4 years ago
Read 2 more answers
Determine algebraically whether the function is even, odd, or neither even nor odd. (2 points)
ahrayia [7]

Answer:

f(x) is neither odd nor even function

Step-by-step explanation:

we are given

f(x)=-3x^4-2x-5

Firstly, we will find f(-x)

we can replace x as -x

we get

f(-x)=-3(-x)^4-2(-x)-5

now, we can simplify it

f(-x)=-3x^4+2x-5

we can see that

it is neither equal to f(x) nor -f(x)

we know that

For even:

f(-x)=f(x)

For odd:

f(-x)=-f(x)

so, f(x) is neither odd nor even function

3 0
3 years ago
Read 2 more answers
Other questions:
  • Devante went to the college traveling 15 mph and returned home traveling 6 mph. if the total trip took 7 hours, how long did dev
    15·1 answer
  • The surface area is the amount a solid can hold.<br><br> True<br> False
    7·2 answers
  • in a school election 1/3 of the students vote. there are 655 ballots. find the number of students at the school
    7·1 answer
  • CAN ANYBODY HELP ME WITH THIS ONE TOO!!!!
    8·2 answers
  • Suppose z=x2sin(y), x=5t2−5s2, y=−6st.
    13·1 answer
  • 2 and 4 are adjacent angles.<br><br> True<br> False
    12·2 answers
  • The number of tenths in 3 3/5
    7·1 answer
  • Can someone just give the the answer please ive asked twice and I can’t get an answer.
    13·1 answer
  • An item has an original price of $80, then discounted 30%. What is the total price after sales tax (.0825)?
    10·2 answers
  • PLEASE HELP ME
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!