A(n) _____ bond joins these two oxygen atoms.

A research team studies a large Eastern Milk Snake population in a metropark. In these snakes, gene T is one gene that affects t

sweet [91]

Answer:

Option E

Explanation:

As per Hardy Weinberg's second equation of equilibrium, the sum of genotype frequency for all possible genotype in a given population with two allele is equal to

$p^2 + q^ 2+2pq = 1\\$

Substituting the given values in above equation, we get -

$0.16 + 0.64 + 0.20 =1\\ p^2+q^2+2pq= 1$

Hence, second equation satisfies.

As per Hardy Weinberg's first equation of equilibrium, sum of all allele frequencies is equal to 1

$p + q=1\\\sqrt{0.16} +\sqrt{0.64} \\0.4+0.8 = 1.2\neq 1$

Hence, this population is not in Hardy weinberg's equation.

After one generation, the frequency of T allele is $0.4$ which is the same as that of frequency of T allele in previous generation

Also as per hardy Weinberg's theory , if a population genotype frequency sums up to 1, it is in equilibrium if its allele frequency sum is also 1.

But here in 2004. This was not the case.

However, Weinberg has stated that the population which is not in equilibrium can reach equilibrium after one generation only with a new set of genotype frequency and allele frequencies.

Hence, in this case there is a possibility that allele and genotype frequencies have readjusted to sum up to 1

If frequency of the T allele is $0.4$

New frequency of the t allele would be

$1- 0.4\\= 0.6$

and New genotype frequencies would be

$p^ 2 = 0.4^2 = 0.16\\q^ 2 = (1-0.4)^2 = 0.36\\2pq = 1-0.16-0.36 = 0.48$

Thus, $p^ 2+q^2+2pq = 1$

Hence, option E is correct

5 0

3 years ago

Investigators are looking for the igniter used at their crime scene. Which igniter is most likely to leave evidence behind for i

Basile [38]

A cigarette lighter considering the suspect touched it and left fingerprints

7 0

3 years ago

Read 2 more answers

Are you 100% sure of the parent’s phenotypes? Are you 100% sure of Maria’s phenotype? If not, which are problematic? Why?

Brut [27]

The provided question lack the essential part which is required to answer the question, however the correct part is attached with with the question as image.

Answer:

From the provided punnett square it is clear that the genotype of parents are Rr for each. On this basis offspring which is maria that can be either RR, Rr, or rr. Maria have chances to get RR= 25%.

There can be no 100 surety of the phenotype of maria as there is 25% chances of rr and 75% of ability of tongue rolling.

to get Rr=50% and rr = 25%