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cricket20 [7]
3 years ago
9

Help me

Mathematics
1 answer:
butalik [34]3 years ago
6 0

Answer:

D. Tenths

Step-by-step explanation:

Because when you go behind the decimal, it starts out with tenths, then hundredths, and then thousandths. And 6 in the 1st spot behind the decimal so it's tenths.

hope I helped.

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Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of $29.
natali 33 [55]

Answer:

250 minutes with the flat rate of $29.

x\leq 250

x would be the number of minutes called.

x-250

Tracy would be charged by $0.35 per minute.

f(x)=29\\ 0\leq x\leq 250

f(x)=0.35(x-250)+29,\\250\leq x\leq ∞

6 0
3 years ago
At the market 5 light bulbs cost 9.85. How much do 7 light bulbs cost?
Leya [2.2K]
The unit rate is $1.97 per lightbulb. Multiply $1.97 by 7 to get 13.79
5 0
3 years ago
Read 2 more answers
The sum of two consecutive ODD integers is -76. Find the integers.​
alexandr1967 [171]

Answer:

First number: -39

Second number: -37

Step-by-step explanation:

An odd number can be written as 2n+1 where n is a whole number.

Let's call our first number 2n+1.

Our second, consecutive number will be 2 more than our first number, since it has to be odd. All numbers go: odd -> even -> odd -> even. If we have an odd number, and add 2, we'll get the next odd number.

First number: 2n+1

Second number: 2n+1+2 = 2n+3

The sum of these two numbers, 2n+1 and 2n+3 will be -76.

(2n+1) + (2n+3) = -76

2n + 2n + 1 + 3 = -76

4n + 4 = -76

4n = -80

n = -20

Since our first number is 2n+1:

2 * (-20) + 1 = -40 + 1 = -39

First number: -39

Our second number is 2n+3, or 2 more than our first number.

-39 + 2 = -37

Second number: -37

We can double check this:

-39 + (-37) = -39 - 37 = -76

7 0
3 years ago
If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, of the box with a square base are described below:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - Side length of the base, in centimeters.

h - Height of the box, in centimeters.

By (2), we clear h within the formula:

h = \frac{V}{l^{2}}

And we apply in (1) and simplify the resulting expression:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Then, we find the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find the critical value of the side length of the base is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Then, we evaluate this result in the expression of the second derivative:

V'' = -600

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

V = 30000\cdot l - l^{3}

V = 2000000\,cm^{3}

The largest possible volume of the box is 2000000 cubic meters.

4 0
3 years ago
Pj will begin her cake deliveries at 12:20. She asked me to remind her 30 minutes befor she has to leave. What time should I rem
algol [13]

Answer:

11:50 is the answer

6 0
3 years ago
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