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2 years ago

What is the length of EF in the right triangle below?

Mathematics

1 answer:

Goshia [24]2 years ago

6 0

Answer:

Its SQUARE ROOT 217

$\sqrt{217}$

AP3X HOPE THIS HELPS

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HELP PLEASE!!!

amm1812

$2300\cdot\frac{6}{100}=23*6=138$ ears of non edible corn

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3 years ago

hallie is trying to win the grand prize on a game show. Should she try her luck by spinning a wheel with 6 equal sections labele

Valentin [98]

I would say she should spin the wheel because, if she rolled the dice it would take a long time to get 2 5's on both dice at one time.
Hope this helps!

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2 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!

gavmur [86]

Answer:

A. 70

Step-by-step explanation:

You can use the transversals and use vertical angles are congruent.

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3 years ago

Read 2 more answers

A shop sells chocolate, vanilla and strawberry ice creams. 45% of the ice creams sold are vanilla, and 1/4 are strawberry. What

OverLord2011 [107]

Answer:

30%

Step-by-step explanation:

Well since we know that 45% is vanilla that means we have part of our answer

Also we know we sold 1/4 strawberry which in percent that would be 25%

If we add 45% with 25% 45+25=70 then since something can only be 100%

100%-70%=30%

you sold 30% chocolate

<3 <;

6 0

2 years ago

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de

OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean $\mu$ = 186 × 17 = 3162

Standard deviation = $29* \sqrt{17}$

Standard deviation = 119.57

$P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})$

$P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})$

$P(X>3417) = P(Z>\dfrac{255}{119.57})$

$P(X>3417) = P(Z>2.133)$

$P(X>3417) =1- 0.9834$

$P(X>3417) =0.0166$

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0

3 years ago