Increasing: (-4,-4)
Decreasing: (4,-2)
Answer:
3/5 X 3 1/2 = 3/5 X 7/2 = 21/10 = 2.1 in²
Step-by-step explanation:
Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula
a) To find the initial amount of this substance
At t=0, we get
We know that e^0=1 ( anything to the power zero is 1)
we get,
The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,
Taking natural logarithm on both sides we get,
Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,
The amount of substance will be present around in 2500 years is 0.000585 grams
Smaller, since a half equals to 0.50
It would be 6+4, which equals 10. Then, subtract 104 ft minus 10 to get 94 ft in depth.