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2 years ago

Three-quarters the product of two numbers m and n. what is it in algebraic expression

Mathematics

1 answer:

Delvig [45]2 years ago

5 0

Answer:

m × n = 3/4

Step-by-step explanation:

Product means to multiply together so the symbol is a multiplication symbol.

I hope it helps! Have a great day!

Lilac~

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Equation of the line that passes through the points (2,3) and (2,5)

sergij07 [2.7K]

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3 years ago

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Oduvanchick [21]

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Step-by-step explanation:

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2 years ago

The Sanchez family uses 2 3/4 tubes of tooth paste each month. How many tubes of toothpaste does the Sanchez family use each yea

Licemer1 [7]

2.75 * 12 = 33.

If the Sanchez family is using 2 3/4 (or 2.75) tubes of toothpaste and there are 12 months in a year, we use the equation above and get 33 as our answer.

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3 years ago

Read 2 more answers

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

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2 years ago

Help show work please

pantera1 [17]

We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by 4x/4x

we get $\frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}$

3 0

3 years ago