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NNADVOKAT [17]
2 years ago
9

What is the name of the shape graphed by the function r = 2 - costheta

Mathematics
1 answer:
Afina-wow [57]2 years ago
8 0

Answer:

limaçon (no inner loop)

Step-by-step explanation:

The equation of a limaçon is written generically as ...

r = b + a·cos(θ)

For b=2 and a=1, this would put the flat side on the left. Rotating it 180° can be accomplished by adding or subtracting π from θ. Then the equation can be ...

r = 2 + cos(θ-π) . . . . or ...

r = 2 - cos(θ)

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solution given:

For Cuboid

length[l]=11mm

breadth [b]=9mm

height[h]=6mm

For semi cylinder

height[H]=11mm

radius[r]=\frac{9}{2}=4.5mm

Now

Totalsurface area=2(lb+bh+lh)+½(2πr(r+H))-l*b[/tex]

:2(11*9+9*6+11*6)+22/7*4.5(4.5+11)-11*9

:438+219.2-99

:558.2mm²

Here area of base is subtracted as it is not included.

<u>T</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>s</u><u>u</u><u>r</u><u>f</u><u>a</u><u>c</u><u>e</u><u> </u><u>a</u><u>r</u><u>e</u><u>a</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>m</u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>e</u><u> </u><u>f</u><u>i</u><u>g</u><u>u</u><u>r</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>:</u><u>5</u><u>5</u><u>8.</u><u>2</u><u>mm²</u><u>.</u>

8 0
3 years ago
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Hope this helps!

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Step-by-step explanation:

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Please help! Solve the following:
mihalych1998 [28]

Answer:

n=10.

Step-by-step explanation:

\frac{45}{n^{2}-3n-4 } - \frac{3}{n-4} = \frac{2}{n+1 }

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\frac{45}{n^{2}-3n-4 } -  \frac{3n+3}{n^{2} -3x-4} = \frac{2n-8}{n^{2} -3x-4 }

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Which of the following is a factor of 30x2 + 37x + 10?
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your answers is A)5x + 2


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