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Reil [10]
3 years ago
10

Please help!! i’m stuck and i’ll give brainliest but i need an explanation for the answer

Mathematics
1 answer:
ehidna [41]3 years ago
8 0

9514 1404 393

Answer:

  -12

Step-by-step explanation:

The average rate of change of a function f(x) on an interval [a, b] is defined as ...

  average rate of change = ((f(b) -f(a))/(b -a)

For the given function and interval, this is ...

  average rate of change = (f(1.25) -f(0.75))/(1.25 -0.75)

  = (4 -10)/(0.5) = -12

The average rate of change is -12 on the interval.

__

The calculator results for f(1.25) and f(0.75) are shown in the attachment, along with the computation of the average rate of change.

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How would you solve for side a? Pythagorean theorem, cause if that's the case wouldn't
Yuri [45]
The angle is 127°, so the Pythagorean theorem does not apply.

Generally, you would use the Law of Cosines to solve for the third side when given two sides and the angle between them.

EF^2 = 7^2 +15^2 -2*7*15*cos(127°)
EF ≈ √(400.3812) ≈ 20.00953

My guess is that you're expected to use 20 for the length of the 3rd side.

By Heron's formula, s = (7 +15 +20)/2 = 21

Area = √(21*(21 -7)*(21 -15)*(21 -20)) = √(21*14*6*1) = √1764 = 42 . . . . yd^2

_____
More directly,
.. Area = (1/2)*7*15*sin(127°) ≈ 41.928 . . . . yd^2

3 0
4 years ago
The location x of a car in meters is given by the function x = 30t - 5t^2 where t is in seconds. At the time when the car is mov
EastWind [94]

So, how far is the car from where it was at t = 0 is 40 m

<h3>Velocity of the car</h3>

Since the location x of the car in meters is given by the function x = 30t - 5t² where t is in seconds, we need to find the time at which its velocity is 10 m/s in the negative direction by differentiating x with respect to t to find its velocity, v.

So, v = dx/dt

= d(30t - 5t²)/dt

= d30t/dt - d5t²/dt

= 30 - 10t

When v is 10 m/s in the negative direction, v = -10 m/s.

So, v = 30 - 10t

-10 = 30 - 10t

-10 - 30 = -10t

-40 = -10t

t = -40/-10

t = 4 s

<h3>The distance at 4 s when its velocity is -10 m/s</h3>

Since at t = 4 s, its velocity is -10 m/s and x = 30t - 5t² is the car's location. The car's distance from t = 0 after its velocity is -10 m/s is

x(4) - x(0) = 30(4) - 5(4)² - [30(0) - 5(0)²]

= 120 - 5(16) - [0 - 0]

= 120 - 80 - 0

= 40 m

So, how far is the car from where it was at t = 0 is 40 m

Learn more about distance of car here:

brainly.com/question/17097458

6 0
3 years ago
A shop sells candles in boxes of 3 for $12.60 each or 1 candle for $5.50. How many candles can Julia buy with $20?
kherson [118]

Answer: the number of scented candles ... x

the number of unscented candles ... y

x + y = 28

$16 * x + $10 * y = $400  ... 16 * x + 10 * y = 400

Step-by-step explanation: This is the equation

16 * (28 - y) + 10 * y = 40016 * 28 - 16 * y + 10 * y = 400448 - 400 = 16 * y - 10 * y48 = 6 * y    /6y = 48 / 6y = 8x = 28 - y = 28 - 8 = 20Result: The candle shop sold 20 scented candles and 8 unscented candles today.

Please give me Brainliest

4 0
4 years ago
The number of citizens in a town is growing according to a linear growth model. The initial population in week 0 was P_0=124 and
il63 [147K]
184 - 124 = 60
so it has grown  by 60 in 18 months. That is 3 1/3 per month.

so Number of citizens depending on month  is 124 + (1 1/3)n
or 124 + 4n/3:

At population 1000:-
124 + 4n/3  = 1000
4n/3 = 1000-124

n  =  (1000-124) * 3/4  =  657 months

5 0
4 years ago
How old am I if 400 reduced by 3 times my<br> age is 229?
Salsk061 [2.6K]

Answer:

57 years old

Step-by-step explanation:

  • 400 - 3x = 229
  • 3x = 171
  • x = 57
  • 400 - 171 = 229
8 0
3 years ago
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