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svetoff [14.1K]

3 years ago

14

69✖️2[8+12-10✖️2+(7-5)-1]-6*

1 answer:

Paul [167]3 years ago

6 0

69×2 [8+12-10×2+ (7-5) -1] -6 69×2 [8+12-10×2+2-1] -6 69×2 [8+12-20+2-1] -6 69×2 [20-20+2-1] -6 69×2 [0+2-1] -6 69×2 [1] -6] 138 [1] -6 138-6 132 I believe this is ur answer.

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If a man can run p miles in x minutes, how long will it take him to run q miles at the same rate?

shusha [124]

The answer will be qx

8 0

3 years ago

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Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya

Gnoma [55]

Answer: If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

$y=5x-1\\\\y-5x=-1$

For the case of Howard :

Equation will be

$y=5x+1\\\\y-5x=1$

For the case of Vincent :

$y=4x+5\\\\y-4x=5$

Since First two equations are parallel so it has no solution.

Reason:

$y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}$

Hence, if two pair is parallel then it has no solution.

8 0

3 years ago

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Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

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3 years ago

A circle has a diameter with endpoints at –2 + i and –6 –11i. What is the center of the circle?

kotykmax [81]

Be more specific. Like what is it asking you to do ? I'm trying to help. :)

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3 years ago

Mary’s trapezoid-shaped garden has a perimeter of 24 yd. She knows the length of three of the sides, 3 yd, 6 yd, and 9 yd.

Anna007 [38]

Answer:

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Step-by-step explanation:

to find the perimeter of a trapezoid you add all the sides together

therefore we do it backwards

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6 0

2 years ago

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