Answer:the first one opn and qps
Step-by-step explanation:
Answer:

And in order to solve this we have two possibilities:
Solution 1

And solving for T we got:


Solution 2
And the other options would be:


Step-by-step explanation:
For this case we can define the variable os interest T as the real temperature and we know that if we are 3 F more than the value of 98.6 we will be unhealthy so we can set up the following equation:

And in order to solve this we have two possibilities:
Solution 1

And solving for T we got:


Solution 2
And the other options would be:


Sophia is more correct in her solution.
Answer:
I disagree
'No it won;t
Step-by-step explanation:
Given the inequality functions;
-2(3 – x) > 2x – 6
Open the parenthesis
-2(3) -2(-x) > 2x - 6
-6 + 2x > 2x - 6
Collect like terms
2x-2x > -6 + 6
0x > 0
x > 0/0
<em>The value of x does not exist on any real number. I disagree with my friend since the value of x is an indeterminate function. If the inequality were ≥, it won't change anything as the value of x won't still exist on any real number </em>
<em></em>
Answer:
x = 94
Step-by-step explanation:
(86 + x)/2 = 90
86 + x = 180
x = 94