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3 years ago

What is the volume of the pyramid?

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

V = 1/3 B * H where B is the area of the base and H is the height

to find the base , we find the area

B = s^2 where s is the side length

V = 1/3 s^2 *H

V = 1/3 * 11^2 * 12

V = 1/3 * 121 * 12

V = 484 cm^3

Choice B

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What is 48% of 72 time 3 divided by 9

devlian [24]

11.52 72×3=216x48÷100÷9= 11.52

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3 years ago

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A bagback that normally sales $39 is on sale for 30% off.Find the amount of the sale price

Ede4ka [16]

If the sale price is 30%, you turn that into a decimal and it will be .3. now you multiply the discount by 39 and it will get you 11.7. 11.7 is the money of discount so now all you have to do is subtract 11.7 from 39 and you shall get 27.3.

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3 years ago

Can someone explain the quadratic formula please?

brilliants [131]

Answer:

While factoring may not always be successful, the Quadratic Formula can always find the solution. The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

source from: https://www.purplemath.com/modules/quadform.htm

your welcome!

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3 years ago

Desmond deposits $50 into a savings account every month at an annual interest rate of

joja [24]

Given:

Desmond deposits $ 50 monthly.

Yearly he deposits = $50×12 = $ 600

Rate of interest compounded monthly = 4.7%

To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.

Formula

$A = P(1+\frac{r}{(n)(100)} )^{nt}$

where,

A be the final amount

P be the principal

r be the rate of interest

t be the time and

n be the number of times the interest is compounded.

Now,

Taking,

P = 600, r = 4.7, n = 12, t = 10 we get,

$A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}$

or, $A = 600(1.0039)^{120}$

or, $A = 959.1$

Now,

At starting he has $ 600

At the end of 10 years he will be having $ 959.1

So,

The amount of change in his account = $ (959.1-600) = $ 359.1

Therefore the rate of change = $(\frac{359.1}{600} )(100) %$

= 59.85%

Hence,

a) His account will contain $ 959.1 after 10 years.

b) The rate of change in his account is 59.85% after 10 years.

7 0

3 years ago

Please help me with question number 2

Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0

2 years ago