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3 years ago

Find the answer to 3(q+34)=2

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

8 0

Hey there!

3(q + 34)= 2

First distribute:

3(q) + 3(34)

3(q) = 3q

3(34) = 102

New equation: 3q + 102 = 2

Subtract by 102 on each of your sides:

3q + 102 - 102 = 2 - 102

Cancel out: 102 - 102 because it gives us 0

Keep: 2 - 102 because it helps us solve for our q

2 - 102 = - 100

New equation: 3q = -100

Divide both sides by 3

3q/3 = -100/3

Cancel out: -3q/3 because it gives us 1

Keep: -100/3 because it gives us the answer for q

Answer: q = -100/3 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

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$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

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The population proportion have the following distribution

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Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

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For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261$

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369$

And the 90% confidence interval would be given (0.261;0.369).

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).

lower limit =0.261

upper limit =0.369

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