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3 years ago

Multiply. -5•-1/7•4/8. Write your answer in simplest form.

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

Answer:

The answer is $\frac{5}{14}$ .

Step-by-step explanation:

1. -5 × $\frac{-1}{7}$ = $\frac{5}{7}$

2. $\frac{5}{7}$ · $\frac{4}{8}$ = $\frac{20}{56}$

3. Simplify:

$\frac{20}{56}$ = $\frac{5}{14}$

Sphinxa [80]3 years ago

7 0

Answer:

5/14

Step-by-step explanation:

Multiply.

(-5 × -1 × 4) / (7 × 8)

20/56

Simplify.

5/14

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Two functions, P and Q, are described as follows: Function P y = 5x + 3 Function Q The rate of change is 2 and the y-intercept i

Svetach [21]

Function P . . . . . y = 5x + 3

Function Q . . . . . y = 2x + 4

Function P rate of change = 5
Function Q rate of change = 2

The first one is => 3 <= more than second one.

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3 years ago

Read 2 more answers

A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The

disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ± 5.09

=-2.09, 8.09 is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0

3 years ago

Show the ratios are equivalent by simplifying any 4 of them.

aliya0001 [1]

When simplified all of them equal 3/1. They are asking you to just chose 4 of them. Hope that helps!

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4 years ago

Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).

QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

$\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}$

Using the section formula expressed as

$[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]$

In this case,

$\begin{gathered} m=1 \\ n=2 \end{gathered}$

where

$\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}$

Thus, by substitution, we have

$\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}$

Hence, the y-coordinate of the point P is