Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Answer:
idk
Step-by-step explanation:
Step-by-step explanation:
I am not allowed to answer more than 3 questions. So I will do the first 3.
15a. i) (2/3) = 4/9
ii) (2/3) = 8/27
iii) (2/3) = 16/81
b. The product is small because you are finding the fraction of a fraction.
16. Compared to the factors, the product is less than each fraction. This is because, as stated above, you are trying to find a fraction (a part of the whole) of another fraction. When you multiply a whole number by a fraction, the whole number decreases. The same applies to a fraction.
17a. 0.4 × 0.3 = 0.12
b. 0.4 = 4/10 = 2/5
0.3 = 3/10
3/10 × 2/5 = 6/50
Ax=15+bx
ax-bx=15
x(a-b)=15
x=15/(a-b)
