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3 years ago

Please help I am very confused!!!!!!!!!

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Answer:

25 units²

Step-by-step explanation:

Area of square = side ²

Area = (6 - 6)² + (7 - 2)²

Area = 5²

Area = 25 units²

ivolga24 [154]3 years ago

3 0

(x,y)
x=right left direction
y=up down direction

we see the points (1,7) and (1,2)
they didn't move anywhere to the right or left since the first number didn't change
it went 5 units down though (7 to 2 is 5 units)

then the next one
look at the ones with same numbers in the same place

(1,7) and (6,7)
didn't move up or down but moved 5 units left and right (1 to 6 is 5 units)

(6,7) and (6,2)
didn't move left or right but moved down 5 units (7 to 2 is 5)

(6,2) and (1,2)
didn't go up or down but went 5 units down (6 to 1 is 5)

so we have that the points are 5 away from each other (the ones that are stright up and left or righ tof each other (not diagonal))

therefor the legnth of each side is 5 units

area=5^2=25

anothe way is
square has 4 sides equal
find 1 side and you found other 3
pick 2 points with same first number or second number and find difference

(1,7) to (1,2)
difference of 5 (7 to 2 is 5)

therefor area=5^2

25 square units

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Answer:

2a^2 + 2a - 11

Step-by-step explanation:

(2a^2-5) +(-6+2a)

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3 years ago

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matrenka [14]

Answer:

The answer is: This statement is true :)

Step-by-step explanation:

8 0

3 years ago

(-4, -2); y = - 2x + 4

padilas [110]

Answer:

y = -2x - 10

Step-by-step explanation:

Slope intercept form of equation is of form

y = mx+c

where m is the slope of line and c is the y intercept of the line.

Y intercept is point on y axis where the line intersects the y axis.

_____________________________

Given equation

y = -2x +4

comparing it with y = mx+ c

m = -2 , c = 4

_____________________________

when two lines are parallel, their slopes are equal.

Let the equation of new line in slope intercept form be y = mx + c

Thus slope of of new required line is -2

Thus m for new line is -2.

now, equation of required line : y = -2x+c

Given that this line passes through (-4, -2). This point shall should satisfy equation y = -2x+c.

Substituting the value of (-4, -2) we have

-2 = -2(-4)+c

=> -2 = 8 +c

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Thus , equation of required line is y = -2x - 10.

8 0

3 years ago

Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3

VashaNatasha [74]

  The correct answer is: Answer choice: [A]:
__________________________________________________________
→  " $\frac{u}{u-3}$ " ; " { u $\neq$ ± 3 } " ;

  →  or, write as: " u / (u − 3) " ;  {" u ≠ 3 "}  AND: {" u ≠ -3 "} ;
__________________________________________________________
Explanation:
__________________________________________________________
We are asked to simplify:

   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note that the "numerator" —which is: "(u² + 3u)" — can be factored into:
  → " u(u + 3) " ;

And that the "denominator" —which is: "(u² − 9)" — can be factored into:
  → "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→ $\frac{u(u+3)}{(u-3)(u+3)}$ ;

___________________________________________________________

→ We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" $\frac{(u+3)}{(u+3)} = 1$ " ;

→ And we have:
_________________________________________________________

→  " $\frac{u}{u-3}$ " ; that is: " u / (u − 3) " ; { u $\neq 3$ } .
and: { u $\neq-3$ } .

→ which is:  "Answer choice: [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ;

and if the denominator is "(u − 3)" ; the denominator equals "0" when "u = -3" ; as such:

"u $\neq$ 3" ;

→ Note: To solve: "u + 3 = 0" ;

Subtract "3" from each side of the equation;

→ " u + 3 − 3 = 0 − 3 " ;

→ u = -3 (when the "denominator" equals "0") ;

→ As such: " u $\neq$ -3 " ;

Furthermore, consider the initial (unsimplified) given expression:

→   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note:  The denominator is: "(u²  − 9)" .

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ;

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________

→ " u² − 9 = 0 " ;

→ Add "9" to each side of the equation ;

→ u² − 9 + 9 = 0 + 9 ;

→ u² = 9 ;

Take the square root of each side of the equation;
to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ;

→ √(u²) = √9 ;

→ | u | = 3 ;

→ " u = 3" ; AND; "u = -3 " ;

We already have: "u = -3" (a value at which the "denominator equals "0") ;

We now have "u = 3" ; as a value at which the "denominator equals "0");

→ As such: " u $\neq 3$ " ; "u $\neq$ -3 " ;

or, write as: " { u $\neq$ ± 3 } " .

_________________________________________________________

6 0

3 years ago

A gentleman is standing 10 feet from a streetlight. He is 5'6 tall and has a shadow of 24 feet. What is the height of the street

Goshia [24]

Answer:

Height of the streetlight ≈ 8 ft(nearest foot)

Step-by-step explanation:

The doc file displays the triangle formed from the illustration. x is the height of the street light. The distance from the gentle man to the street light is 10 ft. He has a height of 5.6 ft and the shadow formed on the ground is 24 ft long. The height of the street light can be calculated below.

The length of the tip of the shadow to the base of the street light is 34 ft. Similar triangle have equal ratio of their corresponding sides .

ab = 5.6 ft

The ratio of the base sides = 24/34

The ratio of the heights = 5.6/x

The two ratio are equal Therefore,

24/34 = 5.6/x

24x = 5.6 × 34

24x = 190.4

divide both side by 24

x = 190.4/24

x = 7.93333333333

x ≈ 8 ft

Height of the streetlight ≈ 8 ft(nearest foot)

Download docx

7 0

3 years ago