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Kay [80]
3 years ago
9

Which of the following functions is graphed below?

Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer:

B.\ y=\left\{\begin{array}{ccc}x^3-2,\ x\leq1\\x^2+4,\ x>1\end{array}\right

Step-by-step explanation:

Look at the picture.

≤, ≥ - closed circle

<, > - open circle

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Solve 4.05p+14.40= 4.50(p+3)
Lubov Fominskaja [6]
We can solve this problem by using PEMDAS 

PEMDAS stands for 
Parenthesis 
Exponents
Multiply
Add
Subtract

So start with (P+3) () is a parenthesis 
5 0
2 years ago
Read 2 more answers
Suppose an ant walks counterclockwise on the unit circle from the point to the endpoint of the radius that forms an angle of rad
serg [7]

Answer:

\frac{4\pi}{3}

Step-by-step explanation:

The original questions is suppose an ant walks counterclockwise on a unit circle from the point (1,0) to the endpoint of the radius that forms an angle of 240 degrees with the positive horizontal axis.

To find the distance ant walked we find the arc length of the sector with central angle 240 degree and radius =1 (unit circle)

arc length of a sector =\frac{centralangle}{360} \cdot 2\pi r

arc length of a sector =\frac{240}{360} \cdot 2\pi(1)

arc length of a sector =\frac{2}{3} \cdot 2\pi

\frac{4\pi}{3}

6 0
3 years ago
Rearrange the formula V = 1 3 πr2h for h. A) h = 3V πr2 B) h = V 3πr2 C) h = 3πr2 V D) h = πr2 3V
stiks02 [169]

Answer:

Option a) h=\frac{3V}{\pi r^{2} }

Step-by-step explanation:

The given formula seems to represent the volume of right circular cone. The correct formula is:

V=\frac{1}{3} \pi r^{2} h

We have to rearrange the formula for h. This means we have to move h on one side of the formula and all the other variables and constants on the other side of the equation. This can be done as shown below:

V=\frac{1}{3} \pi r^{2} h\\\\3V=\pi r^{2} h\\\\h=\frac{3V}{\pi r^{2} }

5 0
3 years ago
Whoever checks my work and tell what I did wrong and the right answer will
gulaghasi [49]

Answer:

See below

Step-by-step explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolatingd_{1}, we need to get rid of the 1/2 first. Let's multiply each side by 2:

2*m = 2*\frac{1}{2}(d_{1}+  d_{2}) \\2m = d_{1}+  d_{2}

After this, we just subtract d_{2} from each side to get d_{1}=2m- d_{2}. Dark Blue is correct! Let's now plug in those numbers below:

d_{1}=2(10)- 13 = 20-13=7

G: Let's isolate the vw^2 on one side by subtracting y from each side:

vw^{2} +y-y=x-y\\vw^{2}=x-y

Let's now divide each side by v, then put each side under a square root to get our final answer:

\frac{vw^2}{v} = \frac{x-y}{v}\\  w^2 =  \frac{x-y}{v}\\\sqrt{w^2} = \sqrt{\frac{x-y}{v}} \\w=\sqrt{\frac{x-y}{v}}

Orange is correct! Again, let's solve the problem underneath:

w=w=\sqrt{\frac{38-(-7)}{5}} = \sqrt{\frac{38+7}{5}} = \sqrt{\frac{45}{5}}=\sqrt{9}=3

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

2a-2a+3c=17a-2a+21\\3c = 15a+21\\\frac{3c}{3} = \frac{15a+21}{3}\\c = \frac{15a}{3}+ \frac{21}{3} \\c = 5a+7

Purple is correct! Let's solve the problem:

c = 5(\frac{16}{5})+7 = 16+7 = 23

7 0
2 years ago
I WILL MARK YOU BRAINLIEST PLEASE !!!!
Illusion [34]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
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