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3 years ago

Which of the following functions is graphed below?

Mathematics

1 answer:

storchak [24]3 years ago

6 0

Answer:

$B.\ y=\left\{\begin{array}{ccc}x^3-2,\ x\leq1\\x^2+4,\ x>1\end{array}\right$

Step-by-step explanation:

Look at the picture.

≤, ≥ - closed circle

<, > - open circle

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If f(x) = –4x2 – 6x – 1 and g(x) = –x2 – 5x + 3, find (f – g)(x).

Leokris [45]

(-4x^2 -6x -1) - (-x^2 -5x +3) = -3x^2 - x - 4

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kkurt [141]

Answer:

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Step-by-step explanation:

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In this question:

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3 years ago

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Ainat [17]

The first equation has no solution

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3 years ago

Which graph represents this function f(x)=1/2x-5

Readme [11.4K]

Answer:

The first graph(Left)

Step-by-step explanation:

Because in this form 1/2 is the slope and -5 is the y intercept.

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3 years ago

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Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

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4 years ago