3(3+5)=6+15 1)3x3 2)3x5 then you up the answers that you get for one and two
I believe it's 37CM, I had that question on my finals last year.
Answer:
2 exponents (2) times 5 exponents (3)
Step-by-step explanation:
To find the prime factors you start by dividing the number by the first prime number which is 2 if there is not a remainder meaning you can divide evenly anymore write down how many 2's you were able to divide by evenly now try dividing by the the next prime factor which is 3 the goal is to get to a quotient of 1

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)
