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2 years ago

14

ES LA OPERACION DE MOVER LOS EJES COORDENADOS EN EL PLANO COORDENADO A UNA POSICION DIFERENTE, MANTENIENDOLOS PARALELOS A LOS OR

IGINALES Y EN EL MISMO SENTIDO

1 answer:

pogonyaev2 years ago

4 0

I don’t not understand what ur asking?

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A swimming pool is to be drained. The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. Su

Gala2k [10]

Answer: it will take 9 hours to empty the pool.

Step-by-step explanation:

The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. It means that when the pool is full, its volume is

30 × 18 × 4 = 2160 ft³

If water is pumped out of the pool at a rate of 216ft3 per hour, then the rate at which the water in the pool is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence(initial amount of water in the pool when completely full).

d represents the common difference(rate at which it is being pumped out)

n represents the number of terms(hours) in the sequence.

From the information given,

a = 2160 degrees

d = - 216 ft3

Tn = 0(the final volume would be zero)

We want to determine the number of terms(hours) for which Tn would be zero. Therefore,

0 = 2160 - 216 (n - 1)

2160 = 216(n - 1) = 216n + 216

216n = 2160 - 216

216n = 1944

n = 1944/216

n = 9

8 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

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3 years ago

PLAY AMONG US WITH ME CODE HNXSPQ SEE U THERE

Kipish [7]

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8 0

3 years ago

Read 2 more answers

How to factor <br> 49y^{2}-9x^{2}

lorasvet [3.4K]

Answer:

(7y + 3x)(7y - 3x)

Step-by-step explanation:

a² - b² = (a + b)(a - b)

49y² - 9x² = (7y)² - (3x)² {a = 7y ; b - 3x}

= (7y + 3x)(7y - 3x)

7 0

3 years ago

1. Determine the approximate measure of angle E.

Naddik [55]

Answer:

1. 81.0

2. I`m trying to figure that out now I will give answers when I can

Step-by-step explanation:

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3 years ago