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ahrayia [7]
3 years ago
10

If y varies directly as x, find the constant of variation if y= 34 when x= 2

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
The answer is C

y=kx. where k is a constant
sub y=34,x=2
2k=34
k=17
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Which of the following points is NOT a solution of the inequality y ≥ Ixl + 3?
omeli [17]

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

5 0
3 years ago
Part A What is the electric field at the position (x1,y1)=(5.0 cm , 0 cm) in component form? Express your answer in terms of the
erik [133]

The complete Question is

A −12 nC charge is located at (x, y)=(1.0 cm, 0 cm).

Part A) What is the electric field at the position (x1, y1)=(5.0 cm, 0 cm) in component form?

Part B) What is the electric field at the position (x2, y2)=(−5.0 cm, 0 cm) in component form?

Part C) What is the electric field at the position (x3, y3)=(0 cm, 5.0 cm) in component form?

Express your answer in terms of the unit vectors i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Answer:

A)  E = - 67500i + 0j N/C

B)   E = 30000i + 0j N/C

C)  E = 8143.18i -  -40715.66j N/C

Step-by-step explanation:

Part A)

Magnitude of the charge = Q = -12 nC = -12 \times 10^{-9} C

Since, its the negative charge, the direction of Electric Field lines will be directed toward the charge

Location of the charge = (1, 0)

We need to find the electric field at point (5, 0)

The formula for the magnitude of electric field due to a point charge is:

E=\frac{kQ}{r^{2}}

Here,

k = Coulomb's Law Constant = 9 \times 10^{9}

Q = Magnitude of the charge

r = Distance between the charge and the point where we need to find the value of E

We can find r by using the Distance Formula.

So,

r=\sqrt{(5-1)^{2}+(0-0)^{2}}=4 cm = 0.04 m

Using these values in the formula, we get:

E=\frac{9\times 10^{9} \times 12 \times 10^{-9}}{(0.04)^{2}}= 67500 N/C

Since, two point (5, 0) is to the right of the given charge (as shown in the first image) i.e. in horizontal direction, all of the electric field experienced by it will be in horizontal direction and the vertical component would be zero. Also the direction of Electric field will be towards the charge i.e. in left direction so the x-component of Electric field will be negative.

Thus, we can write the value of E in vector form to be:

E = - 67500i + 0j N/C

Part B)

We need to find the Electric Field at point (-5, 0)

Using the similar procedure as used in the previous step, first we find r:

r=\sqrt{(-5-1)^{2}+(0-0)^{2}}=6 cm = 0.06

Using the values in the formula of Electric field, we get:

E = \frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.06)^2}=30000 N/C

In this case again, the point is located in a horizontal direction to the given charge, so all the Electric Field experienced by it will be in horizontal direction and the vertical component will be zero. The direction of Electric field will be towards the charge i.e towards Right, so the x-component will be positive in this case.

So, value of the electric field in component form would be:

E = 30000i + 0j N/C

Part C)

We need to find the value of electric field at the point (0, 5). First we find the value of r:

r=\sqrt{(1-0)^2+(0-5)^2}=\sqrt{26}=5.1 cm = 0.051 m

Using the values in the formula of E, we get:

E=\frac{kQ}{r^{2}}=\frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.051)^{2}}=41522 N/C

The point (0, 5) is neither exactly to the left or exactly up. So, for this point we need to find both the horizontal and vertical components as shown in the 2nd figure below.  

From the triangle, we have the opposite and adjacent side to the angle, so using the tangent we can find the value of angle theta.  

tan(\theta)=\frac{5}{1}\\\theta=tan^{-1}(5)=78.69

The two angles shown in the figure will be equal as there are alternate interior angles. Now the angle which E will make with positive x-axis will lie in the 4th quadrant as it lies below the horizontal line. So, the angle with positive x-axis would be:

360 - 78.69 = 281.31 degrees

Ex = E cos(θ) = 41522 cos(281.31) = 8143.18 N/C

Ey = E sin(θ) = 41522 sin(281.31) = -40715.66 N/C

So, in component form the Electric field will be:

E = 8143.18<em>i</em> -  -40715.66<em>j</em>

3 0
3 years ago
Level D
nasty-shy [4]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
Describe the cross-section of the rectangular prism
ser-zykov [4K]

Answer:

The cross-section of the rectangular prism is a:

  • <u>rectangle</u>

Step-by-step explanation:

When you take a cross-section of a rectangular prism, regularly <u>you will obtain a rectangle because this was the base or the two-dimension figure that was used to form the three-dimension figure, in this case, the rectangular prism</u>, the form of obtaining other figure is using how reference the square face, in that case, the cross-section would be a square, this happens because the cross-section is bind with the reference face. Possibly you think the cross-section in the figure doesn´t appear a rectangle, <u>this happens by the perspective because we are looking at the rectangular prism with an inclination of 45°, but if the inclination was 90°, you would see a blue rectangle</u>.

6 0
3 years ago
Sophie can type 128 words in three minutes how many minutes will it take her to type 576 words?
Savatey [412]

Answer:

13 minutes and 30 seconds

Step-by-step explanation:

Okay so first you would divide 128 by 576. But since it takes her 3 minutes just to type 128 words you have to multiply 4.5 times 3. It will take her 13.5 minutes to type 576 words or 13 minutes and 30 seconds.

7 0
3 years ago
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