Question

What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0)?

Answer 1

Answer:

y - 5  = (-5)(x -2) is the required line equation.

The first blank = 5

Second blank = (-5)

Step-by-step explanation:

Here, the two points are given as A(2,5) and B (3,0).

SLOPE of a line with points (a,b) and (c,d) is given as

$m = (\frac{d- b}{c-a})$

Now, here the Slope of line AB is given as  $m = (\frac{0- 5}{3-2}) = \frac{-5}{1} = - 5$

or, the slope of line AB = -5

by POINT SLOPE FORMULA:

The equation of line with point (x0,y0) and slope m is given as

y - y0 = m (x -x0)

So, here the point (2,5) and slope (-5), the equation of line is given as:

y - 5  = (-5)(x -2)

Now, comparing the above line equation with :  y - __ = __ (x - 2)

We get :  The first blank = (5)

                Second blank = (-5)