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Tcecarenko [31]
3 years ago
8

How does density help scientists?

Physics
2 answers:
zimovet [89]3 years ago
8 0
This quantity ρ is known as the density<span> , which is usually defined as the mass per unit volume: ρ = m/V. The volume units milliliter (mL) and cubic centimeter (cm</span>3<span>) are almost identical and are commonly used interchangeably. The general meaning of </span>density<span> is the amount of anything per unit volume.</span>
Alisiya [41]3 years ago
4 0
"Density helps scientists by determining the characteristics of a material."
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Can anyone plz help me ​
juin [17]

Answer:

D,B,C,A,C

Explanation:

I believe that is the correct answers but it is unclear. I don't think the key for the second last question would let the current flowing so the bulb would be off.

8 0
3 years ago
Can peer pressure affect a person social health
notka56 [123]
Yes. Here is my explaination: Peer pressure is a complicated area. On one hand, it can help your child develop the coping skills necessary for adulthood. It can also, however, lead them in bad directions. While teens may feel they have “grown up,” their brains are not finished developing and one of the immature functions is judgment. Peer pressure might encourage teens to become more active in athletics or to avoid risky behaviors. Or it could lead them to try alcohol or drugs, skip school or engage in other negative behaviors.

HOPE THIS HELPS TO ANSWER YOUR QN!
5 0
3 years ago
A uniform ladder is 10 m long and weighs 400 n. it rests with its upper end against a frictionless vertical wall. its lower end
Nikolay [14]
<h3><u>Answer;</u></h3>

200 N

<h3><u>Solution;</u></h3>

Given ;

Weight = 400 N

Length of the ladder = 10 m

Using the equation;

Torque = d x F, where F is the perpendicular force and d is the distance

Calculating torque about the lower end,

Tweight = Twall

400N(5cos30) = F (10sin30)

 F = 200 N

Therefore, the magnitude of force exerted on the peg by the ladder is 200 N

5 0
4 years ago
The revenue (in dollars) for selling q items is given by R ( q ) = 348 q − 2 q 2 and the costs (in dollars) of producing q items
Dvinal [7]

The quantity of 72 that gives the maximum profit of 10268

<u>Explanation:</u>

The profit function p(q) is given by the difference between the revenue and the cost function,

                   P(q) = R(q) - C(q)

The revenue (in dollars) for selling q items is given by  R(q)=348 q-2 q^{2}

The costs (in dollars) of producing q items is given by C(q)= 100 + 60q

             P(q)=348 q-2 q^{2}-(100+60 q)

             =348 q-2 q^{2}-100-60 q

             =-2 q^{2}+288 q-100

The above profit function is a downward opening parabola. Its maximum value occurs,

           \text { At } x=-\frac{b}{2 a}=-\frac{288}{2(-2)}=72

Maximum value, p(72)=\left(-2 \times 72^{2}\right)+(288 \times 72)-100=-10368+20736-100=10268

6 0
4 years ago
One day when you come into physics lab you find several plastic hemispheres floating like boats in a tank of fresh water. Each l
frez [133]

To solve this problem we will first proceed to find the volume of the hemisphere, from there we will obtain the mass of the density through the relation of density. Finally the mass of the stone will be given between the difference in the mass given in the statement and the one found, that is

The volume of a Sphere is

V = \frac{4}{3} \pi r^3

Then the volume of a hemisphere is

V =\frac{1}{2} \frac{4}{3} \pi r^3

With the values we have that the Volume is

V =\frac{1}{2} \frac{4}{3} \pi (8.4/2)^3

V = 155.17cm^3

Density of water is

\rho = 1g/cm^3

And we know that

\text{Mass of water displaced} = \text{Density of water}\times \text{Volume of hemisphere}

m = 1g/cm^3 * 155.17cm^3

m = 155.17g

So the net mass is

\Delta m = m_s-m_w

\Delta m = 155.17-23

\Delta m = 132.17g

Therefore the mass of heaviest rock is 132.17g or 0.132kg

4 0
3 years ago
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