All categories

3 years ago

Can anyone plz help me

Physics

1 answer:

juin [17]3 years ago

8 0

Answer:

D,B,C,A,C

Explanation:

I believe that is the correct answers but it is unclear. I don't think the key for the second last question would let the current flowing so the bulb would be off.

You might be interested in

Two charges are placed on the x axis. One of the charges (q1 = +7.7 µC) is at x1 = +3.1 cm and the other (q2 = -19 µC) is at x2

Alinara [238K]

Answer:

a) $E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

b) $E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

Explanation:

Given that

q1 = +7.7 µC is at x1 = +3.1 cm

q2 = -19 µC is at x2 = +8.9 cm

We know that electric filed due to a charge given as

$E=K\dfrac{q}{r^2}$

$E_1=K\dfrac{q_1}{r_1^2}$

$E_2=K\dfrac{q_2}{r_2^2}$

Now by putting the va;ues

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.031^2}\ N/C$

$E_1=72.11\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.089^2}\ N/C$

$E_2=21.58\times 10^{6}\ N/C$

The net electric field

$E=E_1-E_2$

$E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

As we know that electric filed line emerge from positive charge and concentrated at negative charge.

Now

distance for charge 1 will become =5.5 - 3.1 = 2.4 cm

distance for charge 2 will become =8.9-5.5 = 3.4 cm

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.024^2}\ N/C$

$E_1=120.3\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.034^2}\ N/C$

$E_2=147.92\times 10^{6}\ N/C$

The net electric field

$E=E_1+E_2$

$E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

7 0

3 years ago

The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C . This field is maintained by vario

velikii [3]

Answer:

$q=5.37*10^{5}C$

Explanation:

If we assume that the Earth is a spherical conductor, according to Gauss's Law, the electric field is given by:

$E=\frac{kq}{r^2}$

Here k is the Coulomb constant, the excess charge on the Earth's surface and r its radius. Solving for q:

$q=\frac{Er^2}{k}\\q=\frac{119\frac{N}{C}(6.371*10^6m)^2}{8.99\frac{N\cdot m^2}{C^2}}\\q=5.37*10^{5}C$

5 0

3 years ago

Mass is a fundamental physical quantity give scientific reason

Lena [83]

Answer:

yes

Explanation:

because it is independent of eachother

8 0

2 years ago

Two hockey pucks, each with a mass of 0.2 kg, slide across the ice and

ruslelena [56]

Answer:

Answe: It's B (apex)

Explanation:

5 0

3 years ago

Which is not a way to accelerate an object?

densk [106]

I would definitely think its B....

3 0

3 years ago

Read 2 more answers

Can anyone plz help me ​

Can anyone plz help me