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alekssr [168]
3 years ago
15

Can anyone plz help me ​

Physics
1 answer:
juin [17]3 years ago
8 0

Answer:

D,B,C,A,C

Explanation:

I believe that is the correct answers but it is unclear. I don't think the key for the second last question would let the current flowing so the bulb would be off.

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What happens to wave length as a wave leaves the air and enters the Perspex
Pavel [41]
Hey There!

The angle of incidence increases and the angle of refraction increases.

Thank You!
6 0
3 years ago
A charge of +2 C is at the origin. When charge Q is placed at 2 m along the positive x axis, the electric field at 2 m along the
sveticcg [70]

Answer:

The value of Q is - 8 C

Explanation:

Given;

the magnitude of first charge = 2 C

position of the first charge = 0

         _ (2m)                            0(+2C)                         +(2m)(Q)

------------------------------------------------------------------------------------

                                                E₁ --------------------------------->                                    

            <------------------------------------------------------------------ E₂

E₁ and E₂ are equal in magnitude but opposite in direction

| E₂ | = | E₁ |

\frac{K*Q}{r^2} = \frac{K*2}{r^2} \\\\\frac{Q}{(4)^2} = \frac{2}{(2)^2}\\\\\frac{Q}{16} =\frac{2}{4}\\\\\frac{Q}{16} =\frac{1}{2}\\\\2Q = 16\\\\Q = 8 \ C

Thus, since E₂ is opposite in direction to E₁, the Q = - 8 C

6 0
4 years ago
Force = mass x acceleration
zloy xaker [14]
The answer is (B 60N) hope it helps and have a good day!
4 0
4 years ago
A light-rail commuter train accelerates at a rate of 1.35 m/s2. How long does it take to reach its top speed of 80.0 km/h, start
Len [333]

Answer:

a) 16.46 seconds.

b) 13.46 seconds

c) 2.67 m/s²

Explanation:

Acceleration = a = 1.35 m/s²

Final velocity = v = 80 km/h = 80\frac{1000}{3600}=22.22\ m/s

Initial velocity = u = 0

Equation of motion

v=u+at\\\Rightarrow 22.22=0+1.35t\\\Rightarrow t=\frac{22.22}{1.35}=16.46\ s

Time taken to accelerate to top speed is 16.46 seconds.

Acceleration = a = -1.65 m/s²

Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=22.22-1.65t\\\Rightarrow t=\frac{22.22}{1.65}=13.46\ s

Time taken to stop the train from top speed is 13.46 seconds

Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Time taken = t = 8.3 s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=22.22+a8.3\\\Rightarrow a=\frac{-22.22}{8.3}=-2.67\ m/s^2

Emergency deceleration is 2.67 m/s²

8 0
4 years ago
Two cars approach one another on opposing lanes of a highway. Car 1 is traveling north at a velocity of 80 km/h and car 2 is tra
fomenos

Answer:

220 km/hr

Explanation:

3 0
3 years ago
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