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Drupady [299]
3 years ago
14

Kramer goes bowling and decides to employ the force of gravity to "pick up a spare." He rolls the 7.0-kg bowling ball very slowl

y so that it comes to rest a center-to-center distance of 0.10 m from the one remaining 1.5-kg bowling pin. 1) Determine the force of gravity between the ball and the pin and comment on the efficacy of the technique. Treat the ball and pin as point objects for this problem. (Express your answer to two significant figures.) nN
Physics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

70.035nN

Explanation:

M₁ = 7.0kg

m₂ = 1.5kg

r = 0.1m

G = 6.67*10⁻¹¹ Nm²/kg

Gravitational force (F) of an object is directly proportional to the product masses and inversely proportional to the square of their distance apart.

F = GM₁M₂ / r²

F = (6.67*10^-11 * 7.0 * 1.5) / (0.1)²

F = 7.0035*10^-10 / 0.01

F = 7.0035 * 10^-8 N

F = 70.035nN

The gravitational force acting on the bowling ball is 70.035nN.

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Explanation:


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Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun but have a much smaller dia
Crank

Answer:

Wn = 9.14 x 10¹⁷ N

Explanation:

First we need to find our mass. For this purpose we use the following formula:

W = mg

m = W/g

where,

W = Weight = 675 N

g = Acceleration due to gravity on Surface of Earth = 9.8 m/s²

m = Mass = ?

Therefore,

m = (675 N)/(9.8 m/s²)

m = 68.88 kg

Now, we need to find the value of acceleration due to gravity on the surface of Neutron Star. For this purpose we use the following formula:

gn = (G)(Mn)/(Rn)²

where,

gn = acceleration due to gravity on surface of neutron star = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Mn = Mass of Neutron Star = Mass of Sun = 1.99 x 10³⁰ kg

Rn = Radius of neutron Star = 20 km/2 = 10 km = 10000 m

Therefore,

gn = (6.67 x 10⁻¹¹ N.m²/kg²)(1.99 x 10³⁰ kg)/(10000)

gn = 13.27 x 10¹⁵ m/s²

Now, my weight on neutron star will be:

Wn = m(gn)

Wn = (68.88)(13.27 x 10¹⁵ m/s²)

<u>Wn = 9.14 x 10¹⁷ N</u>

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3 years ago
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