Answer:

Explanation:
It is given that,


Taking the cross product of v and v such that,




|w| = 13.92
Let
is the unit vector normal to the plane containing u and v. So,


Hence, this is the required solution.
the second option is your answer to what a liquid is
Answer:
Explanation:
Important here is to know that due north is a 90 degree angle, due east is a 0 degree angle, and due south is a 270 degree angle. Then we find the x and y components of each part of this journey using the sin and cos of the angles multiplied by each magnitude:

Add them all together to get the x component of the resultant vector, V:

Do the same to find the y components of the part of this journey:

Add them together to get the y component of the resultant vector, V:

One thing of import to note is that both of these components are positive, so the resultant angle lies in QI.
We find the final magnitude:
and, rounding to 2 sig dig's as needed:
1.0 × 10² m; now for the direction:
58°
Answer:
a) 1.725*10^5 N
b) 3.83*10^3 N
c) i) 173.24 kN
c) ii) 4.57 kN
Explanation:
See the attachment for calculations