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k0ka [10]
3 years ago
5

Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP

Mathematics
2 answers:
Sliva [168]3 years ago
6 0

The answer to this query is AA similarity postulate. <span>

<span>Because the triangles given are only similar in angle but dissimilar in sides which makes it incongruent with respect to the sides, AA similarity postulate is the exact answer. 

SAS ASA are not possible answers. </span></span>

ivolga24 [154]3 years ago
3 0
Measure each of your sides make sure all of your sides are even/similar (LMQ & LNP)

So, AA Similarity Postulate (option C)

The rest of the options are false to this problem!

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Option 1:<br><br> Find x. Show all work.
Ronch [10]

Using law of cosines:

Cos(angle) = adjacent/ hypotenuse


Cos(22) = 12/x

Rewrite to get:

X = 12/cos(22)

Simplify:

X = 12.9424

Round the answer as needed.

5 0
3 years ago
Read 2 more answers
A. - 3x - 2y = 4
weeeeeb [17]

Answer:it’s .a

Step-by-step explanation:

7 0
3 years ago
I'd really appreciate some help on these questions, I'm really struggling
nikklg [1K]
We can use linear combinations of the equations to eliminate variables.

3x - 4y = 1
-2x + 3y = 1

To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second. 

9x - 12y = 3
-8x + 12y = 4

Adding,
x = 7

We could solve for y directly but let's use another linear combination, twice the first plus three times the second:

2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)

y = 5

Check: 3(7)-4(5)=1 good.   -2(7)+3(5)=1 good.

Q18 Answer: (7,5)

y = -3x + 5
5x - 4y = -3

4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good

Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good   2y+24=2(-7)+24=10=x good

Q20 Answer (10,-7)


3x + y = 18
-7x + 3y = -10
9x  + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6

Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

Q21 Answer: (4,6)

6 0
3 years ago
a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2
mixer [17]

Answer:

1)Area of the Land  is 48 square meters

2) Area of flower bed   is  28.26 square meter

3)Area of land excluding flower bed   is 19.74 square meters

4)cost of planting grass in land  excluding flower bed   is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot =  6m

Radius of the circular flower bed = 3m

1)Area of the Land  

Area of the Rectangular plot  = Area of the Land  

Area of the Land   = length x width

Area of the Land   =  8*6

Area of the Land  = 48 square meters-----------------------------(1)

2. Area of flower bed

Area of flower bed =  4 x area of one quadrant

Area of flower bed =  area of the circle

Area of flower bed  = \pi r^2

where r is the radius

Now , substituting the values

Area of flower bed = \pi (3)(3)

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed =  Area of the rectangular land - area of flower beds

Area of land excluding flower bed =  48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have  19.74 square meters. to plant grass  for this 19. 74 square meters, the cost will be

=19. 74 \times 6

= Rs 118.44

6 0
4 years ago
HELP are all three of these are either
4vir4ik [10]

the first is no triangles, second Multiple Triangles, third Multiple Triangles

Step-by-step explanation:

6 0
3 years ago
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