Answer:
discriminant: 241
2 real roots
Step-by-step explanation:
The discriminant is the part of the quadratic equation that is under the sqare root
x=(-b±√(b²-4ac))/2a
discriminant: b²-4ac
We also know that a quadratic equation is in the form ax²+bx+c = 0, so we can plug in the values we know from our equation to find the discriminant.
a=4
b=-17
c=3
(-17)^2-4(4)(3)
We also know that if the discriminant
is positive we have 2 real roots
is 0 we have 1 real root aka a repeated real solution
is negative we have no real roots
Answer:
24 premium tickets were sold.
Step-by-step explanation:
Let :
Deluxe ticket = x
Regular tickets = x + 78
Premium tickets = y
x + (x + 78) + y = 208
4x + 2(x+78) + 10y = 714
2x + y = 208 - 78
4x + 2x + 156 + 10y = 714
2x + y = 130 - - - - - (1)
6x + 10y = 558 - - - - (2)
Now we can solve the simultaneous equation using elimination method :
From (1)
y = 130 - 2x
Put y = 130 - 2x in (2)
6x + 10(130 - 2x) = 558
6x + 1300 - 20x = 558
- 14x = 558 - 1300
-14x = - 742
x = 742 / 14
x = 53
Put x = 53 in y = 130 - 2x
y = 130 - 2(53)
y = 130 - 106
y = 24
A quotient of 3 with 28 as a remainder means that 43 fits inside our number 3 times, and you have 28 more units as a remainder.
So, our number is
To write another division problem that has a quotient of 3 and a remainder of 28, we simply choose another number to substitute 43 in the expression above. For example, if we choose 100, the expression becomes
Which means that 328 has quotient of 3 with 28 as a remainder when divided by 100.
The markup is $46.25 and the final price is $231.25
