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djverab [1.8K]
2 years ago
13

How to make 1/3 and 1/1/2 into a 1

Mathematics
1 answer:
dedylja [7]2 years ago
7 0

Answer:

you divide

Step-by-step explanation:

you divide

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What is the answer to this problem
mr_godi [17]

Answer:

I think its the second one

Step-by-step explanation:

the other ones are fair and have a 50% chance on choosing.

  • I am so srry if I'm wrong but I'm pretty confident.
7 0
2 years ago
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For Greta's birthday party, her parents ordered 6 pizzas. If they cut the pizzas into sixths, how many pieces will there be? Cho
saw5 [17]

Options aren't avaible

Answer:

(1 ÷ 1/6) * 6

36 pieces of pizza

Step-by-step explanation:

Given that :

Number of pizzas ordered = 6

Divisions per pizza = 1/6 ;

Hence, 1 full pizza is divided into 1 ÷ 1/6 = 1 * 6/1 = 6 pieces

6 * 1/6(1)

The total pieces of pizzas equals :

6 pieces per pizza * number of pizzas

6 * 6

= 36 pieces of pizza

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3 years ago
What is f(-x), if f(x)=2|x|+3x
a_sh-v [17]
F(-x) = 2/-x/ + 3(-x) = 2/x/ - 3x;
6 0
3 years ago
Determine the value of x<br> 2.12 units<br> 2.02 units<br> 12.38 units<br> 0.49 units
Olin [163]
I believe the answer is 2.02
8 0
3 years ago
There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3
jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0
3 years ago
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