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3 years ago

∑from 1to infinity of n^2* e^-2n

Mathematics

1 answer:

Naily [24]3 years ago

3 0

∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768

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the size of Minnesota is 8.69×10^4 square miles. the size of wisconsin is 65,500 square miles. how many times greater is the siz

Alexxandr [17]

Answer:

Step-by-step explanation:

Minnesota: 86900 square miles

Wisconsin: 65000 square miles.

Net form

86900 - 65000 = 21900 square miles.

Standard Form

86900/65000 = 1.33

Minnesota is 1.33 times as large as Wisconsin.

Scientific notation

1.33 * 10^0

Minnesota is still 1.33 times as large as Wisconsin

5 0

3 years ago

The average of the degree measures of all angles of an octagon is less than the average of the degree measures of all angles of

agasfer [191]

Octagon - 135 degrees

Decagon - 144 degrees

135 / 144 * 100% = 93.75%

Therefore it is 6.25% less

source 1728.com/polygon.htm

7 0

4 years ago

PLEASE HELP! What is the value of x? Enter your answer in the box. x =

Westkost [7]

2√3

hope it helps...!!!

8 0

2 years ago

Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$