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ololo11 [35]
3 years ago
14

∑from 1to infinity of n^2* e^-2n

Mathematics
1 answer:
Naily [24]3 years ago
3 0
<span>∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768</span>
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Friday can what is the greatest parameter of a rectangle with an area of 39 ft.²
victus00 [196]
The greatest perimiter
let's experiment weather we want to have sides with as close to each other as possible, or with as far apart form each other

so if we have lenth times width, peimiter=legnth+legnth+widht+width

1 times 39:perimiter=80
3 times 13:perimiter=52


so we want one side as small as possible
0.1 times 360:perimiter=720.2

let's see how far we can go
0.00000000000000000001 times 3600000000000000000000=3,600,000,000,000,000,000,000.00000000000000000001

you get the idea
that is a really big perimiter
if you can be that exact

so just make a really small decimal

if you haven't learned decimals yet and only know whole numbers then
80 ft is the greatest perimiter made (with sides of 39,1,39,1)
5 0
3 years ago
Read 2 more answers
Completing the sqaure <br> x^2+14x+34
DiKsa [7]

Answer:

-7-√15

Step-by-step explanation:

First move the constant to the right hand side and change it's sign

x^2+14x=-34

Then add (14/2)^2 or 7^2 to both sides

x^2+14x+49=-34+49

Then factor the expression

(x+7)^2=-34+49

Then solve (x+7)^2=15

You should get:

x=-√15-7

or

x=√15-7

7 0
3 years ago
Fractions is greater than 2/5 and less than 3/5?
taurus [48]

Answer:

1/2

Step-by-step explanation:

6 0
3 years ago
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The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?
denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5

All sides have the same lengths.

2. Find the slopes of all lines:

PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}

Since the slopes of PQ and RS are the same, lines PQ and RS are parallel. Since the slopes of QR and SP are the same, lines QR and SP are parallel.

The slopes \frac{4}{3} and -\frac{3}{4} have the product of

-\dfrac{3}{4}\cdot \dfrac{4}{3}=-1,

then lines are pairwise perpendicular.

This means PQRS is a square.

4 0
3 years ago
What is the mean? If the answer is a decimal, round it to the nearest tenth.<br>​
Rasek [7]

Answer:

Round out to the nearest 10th say 5 it would stay 5 unlike 8 would round to 10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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