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ololo11 [35]
3 years ago
14

∑from 1to infinity of n^2* e^-2n

Mathematics
1 answer:
Naily [24]3 years ago
3 0
<span>∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768</span>
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