Question

X2-8x+12=0 Someone help me

Answer 1

$\large\boxed{\tt\:Question}$

x² - 8x + 12 = 0

Hello meremyj! Here's your answer with explanation.

$\large\boxed{\tt\:Answer\:with\:Explanation}$

$x ^ { 2 } - 8 x + 12$

Use the biquadratic formula =》 $x=\frac{-b±\sqrt{\left(-b\right)^{2}-4 ac}}{2}$

Now,

•    b = 8

•    c = 12

•    a =  1

Using the biquadratic formula & substituting the values....

$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 12}}{2} \\x=\frac{-\left(-8\right)±\sqrt{64-4\times 12}}{2} \\x=\frac{-\left(-8\right)±\sqrt{64-48}}{2} \\x=\frac{-\left(-8\right)±\sqrt{16}}{2} \\x=\frac{-\left(-8\right)±4}{2} \\\underline{\underline{x=\frac{8±4}{2}} }$

Now, solve when  $x=\frac{8+4}{2}$

$x=\frac{8+4}{2}\\x=\frac{12}{2} \\\boxed{\bf\:x=6 }$

Now, solve when $x = \frac{8-4}{2}$

$x = \frac{8-4}{2}\\x = \frac{4}{2}\\\boxed{\bf\:x=2}$

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• The value of  x  can be 6 & 2.

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Hope it'll help you!

Lucäžž

Answer 2

Answer:

THE ANSWER IS 0.............