Answer:
55.93°
Step-by-step explanation:
In this problem, we need to find the cos ratio of x, the ratio of the adjacent side of x to the hypotenuse.
The adjacent side of x is 14 and the hypotenuse is 25.
cos x=14/25=0.56=cos 55.93°
Answer:
81/16 = 5 1/16
Step-by-step explanation:
-4(square root of x) -3 = -12
Add 3 to both sides
-4(square root of x) = -12 +3 = -9
Divide both sides by -4
(square root of x) = -9/-4
-/- equals +
(square root of x) = 9/4
Square both sides to cancel the square root
x = (9/4)^2 = 81/16 = 5 1/16
Answer:
Step-by-step explanation:
Using the rule of exponents
![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
⇔ 
, then
![\sqrt[6]{7^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B7%5E%7B2%7D%20%7D)
= 
=
Answer: The probability of selecting at least one boy (the probability that the 2 students selected are not both girls) is 62/95 or 0.6526
Step-by-step explanation:
From the question, the students to be chosen must be selected from a group of eight boys and twelve girls. This means that the total number of students that these two students must be chosen from is:
8 + 12 = 20 students.
The next step would be to find the probability of selecting a boy:
= Total number of boys/Total number of students
= 8/20
We will also find the probability of selecting one girl from the group
= Total number of girls/Total number of students
= 12/20
To find the probability that the two selected students are not girls is the same as finding the probability of selecting at least one boy. To do this, we will first find the probability of choosing all girls and then subtract it from 1.
The probability of selecting or choosing 2 girls (without replacement)
(12/20) × (11/19)
= 132/380
= 33/95
Then, the probability of selecting at least one boy (the probability that the students chosen are not both girls)
= 1 - (33/95)
= (95/95) - (33/95)
= 62/95 or 0.6526
33.3333....,... difference I believe
