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Archy [21]
3 years ago
15

Find the value of In(-7).

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0
The answer is D


I’m right trust
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Find the area of the shaded region.
Ghella [55]
This is a rhombus and in any rhombus, the diagonals intersects in the middle and they are perpendicular:
So all 4 triangles are right triangles and the sides are the hypotenuses.
1st) Calculate the sides: hypotenuse² = 3² + 4² = 25, and hypotenuse = 5

The area of each right triangle is (4 x 3)/2 = 6 units²
And the area of the 4 right triangles = 4 x 6 = 24 init²

4 0
3 years ago
Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −
larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = \frac{3}{2}

d) zeros of the function are x = \frac{-4}{3}  and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1)         (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2        

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = \frac{3}{2}

Thus,

zeros of the function are x = \frac{3}{2}

d)   k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = \frac{-4}{3}

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17        

Thus,

zeros of the function are x = \frac{-4}{3}  and, x = 17

7 0
3 years ago
Somebody help me please !!asap
goldfiish [28.3K]

Answer:

(21, 5)

Step-by-step explanation:

y = -x

y = -(-7)

y = 7

The point is reflected, so it is equidistant on both sides of the reflection line. It takes 14 units to get to the reflection line, -7 + 14 = 7 (the reflection line).

So, another 14 on the other side would be 14 + 7 = 21

:)

4 0
3 years ago
Read 2 more answers
Points B, D, and F are midpoints of the sides of ACE. EC = 32 and BF = 2x - 10. Find the value of x.
Svetlanka [38]

Answer:

13

Step-by-step explanation:

Remark

This only works if B is between AC and F is between AE

Givens

CE = 32

BF = 1/2 CE        Properties of midpoints. BF is parallel to and 1/2 of CE

BF = 1/2 * 32

BF = 16

Equation

2x - 10 = 16                      Add 10 to both sides

2x - 10 + 10 = 16 + 10      Combine    

2x = 26                            Divide by 2

2x/2 = 26/2                     Do the division

x = 13

4 0
4 years ago
If AB = AC, which statement is FALSE?
Setler [38]
Rohanfighter is right, it's D
7 0
3 years ago
Read 2 more answers
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