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allsm [11]
3 years ago
11

1. The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of

positions measured with the best Earth-based optical telescopes. If you cannot measure an angle smaller than this, what is the maximum distance at which a star can be located and still have a measurable parallax
Physics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

Explanation:

each grid corresponding  0.1s⁻¹.

0.2grid unit = 0.2×0.1 =0.02s⁻¹

distance of the star from telescope

d = 1/p

d= 1/0.02= 50 par sec

1par sec = 3.26 light year

1 light year = 9.5×10¹²km

3.26ly=3.084×10¹³km

d= 50×3.084×10¹³=1.55×10¹⁵km

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A rubber toy duck is at rest on an inclined plane. When the angle of inclination of the plane is increased to 36.0°, the toy duc
ch4aika [34]

Answer

toy begins to slide when the plane is at an angle of 36.0°

at this point the toy has just overcome the static friction

f_s = \mu_s N

f_s = \mu_s mgcos \theta

since toy begins to slide

f_s = mgsin \theta

now on comparing

mgsin \theta = \mu_s mgcos \theta

\mu_s = tan \theta

\mu_s = tan (36^0)

\mu_s = 0.726

as the body is moving at constant velocity acceleration will be zero

so now,

m g sin \theta - f_k = ma

m g sin \theta - \mu_k mg cos\theta = 0

\mu_k = tan \theta

\mu_k = tan (29^0)

\mu_k = 0.554

3 0
3 years ago
Plz, help the rubber ball be dropped from the top of a ladder. It bounces on the same spot on the ground several times to a less
Vladimir [108]

Answer:

What do you mean?

Explanation:

6 0
3 years ago
The main advantage banking services offer is?
KATRIN_1 [288]
In short, and in general:

Advantages

<span>Credit Unions typically pay higher dividend rates on savingsCredit Unions typically offer lower rates on loansCredit Unions typically provide better service; since they are owned and governed by their membership, they tend to prioritize the needs of their members above all elseCredit Unions operate on a not-for-profit business model, so excess earnings are returned back to the membership in form of competitive rates and lower fees, and sometimes even special dividendsMany Credit Unions offer the same products and services found at banksCredit Unions often have added-value benefits, such as free financial education, discounted theme park tickets, and special member rates for services such as home alarm systems...even discounts at online retailers like Barnes & Noble.</span>Disadvantages

<span>Credit Unions, and in particular smaller local credit unions, struggle to match the level of convenience (ATMs and branches) that many banks provide their customers, although many CUs are part of shared networks which enhance the breadth of delivery channels available to their membersSome Credit Unions are limited in their product offeringsOne must qualify for membership <span>One must pay a membership fee to join. hope this helps!

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7 0
3 years ago
The sales price of a product is $2 per unit; the variable cost is $1 per unit; and fixed costs total $1,000. how many units must
irakobra [83]

Answer:

<u><em>1000 units for breakeven</em></u>

Explanation:

Let x be the number of units sold at breakeven.

The total sales at the point would be $2x.

Variable costs would be $1x and fixed costs are $1000.

Total costs are = $1x + $1000

At breakeven: Sales = Costs

Sales =m Costs

$2x = $1x + $1000

$1x = $1000

x = 1000 units.

At 1000 units the sales are equal to the costs ("breakeven").

4 0
2 years ago
A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find
pshichka [43]

Answer:

0.050 m

Explanation:

The strength of the magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0=4\pi \cdot 10^{-7} H/m is the vacuum permeability

I is the current in the wire

r is the distance from the wire

And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.

In this problem, we have:

I=1.41 A (current in the wire)

B=5.61\mu T=5.61\cdot 10^{-6} T (strength of magnetic field)

Solving  for r, we find the distance  from the wire:

r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m

4 0
3 years ago
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