Ask question

Ask question

All categories

3 years ago

15

A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete

is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ $F_x=mgSin \theta=ma$

⇒ $a_x=gSin \theta$

$=9.8 \ Sin35^{\circ}$

$=5.62 \ m/s^2$

(b)

If friction present,

⇒ $F_x=mgCos \theta$

⇒ $F_x=mgSin \theta-\mu_r mgCos \theta$

⇒ $a=gSin \theta-\mu_rgCos \theta$

$=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}$

$=5.46 \ m/s^2$

You might be interested in

If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed

Alisiya [41]

Answer:

speed=d/t.

s=4/5=0.8m/s.

4 0

3 years ago

What are the effects/impacts of electromagnetism to our world??

yaroslaw [1]

Answer: Here's your answer: The great uses of Electromagnetism in Life. Whatever powered devices we use, from table clocks to microwave ovens, have some form of electromagnetic principle involved in their functioning. It is electromagnetism which has given the flexibility for switching of/on electricity as required.

Explanation: Yw and mark me as brainiest

7 0

2 years ago

Read 2 more answers

Rank in terms of momentum

eduard

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

$P=m*v$

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

A)

$P = 10000*0\\P=0$

B)

$P=100*5\\P=500[kg*m/s]$

C)

$P=1200*15\\P=18000[kg*m/s]$

D)

$P=15*1000\\P=15000[kg*m/s]$

From higher to lower momentum

C,D,B,A

7 0

2 years ago

Which is at rest relative to a seated passenger in a moving car?

AnnyKZ [126]

THAT'S EASY BRO! the answer is the Seat!

5 0

3 years ago

Read 2 more answers

Please Help !!!!!!!!!!!!!!!!!!!!!!!!!!

larisa [96]

As per the question the wavelength of spectral line of the neutral hydrogen atom is 21 cm.

Spectral line of hydrogen atom will be observed when an electron will jump from higher excited to the ground state. If E is the energy of the ground state and E' is the energy of the higher excited state,the energy emitted when electron will jump from higher excited to ground state is E'-E.

As per Planck's quantum theory -

$hf =E'-E$

Where f is the frequency of emitted radiation and h is the Planck's constant.Actually this energy emitted is also electromagnetic in nature. We know that all the electromagnetic radiation will move with the same velocity which is equal to the velocity of light.

The velocity of light c= 3×10^8 m/s.Hence the velocity of wave corresponding to this spectral line is 3×10^8 m/s.

We know that velocity of a wave is the product of frequency and wavelength of that corresponding wave. Mathematically we can write it as-

$v=\lambda f$

[ $here \lambda$ is the wavelength of the wave ]

It is given that wavelength =21 cm=0.21 m

The frequency is calculated as -

$f=\frac{v}{\lambda}$

$=\frac{c}{\lambda}$

$=\frac{3*10^{8} m/s }{0.21 m}$

$=14.2857*10^{8} s^{-1}$

Hence the antenna will be tuned to a frequency of 14.2857×10^8 Hz

Here Hertz[ Hz] is the unit of frequency.

7 0

3 years ago