Answer:
Elements in Group 14 could lose four, or gain four electrons to achieve a noble gas structure. In fact, if they are going to form ions, Group 14 elements form positive ions. Carbon and silicon form covalent bonds. Carbon's millions of organic compounds are all based on shared electrons in covalent bonds.
Explanation:
Answer:
s = 1.7 m
Explanation:
from the question we are given the following:
Mass of package (m) = 5 kg
mass of the asteriod (M) = 7.6 x 10^{20} kg
radius = 8 x 10^5 m
velocity of package (v) = 170 m/s
spring constant (k) = 2.8 N/m
compression (s) = ?
Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore
• Ei = Ef
• Ei = energy in the spring + gravitational potential energy of the system
• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}
• Ef = kinetic energy of the object
• Ef = \frac{1}{2}mv^{2}
• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}
• s =
s =
s = 1.7 m
C → A → E → D → F → H → G → I → B
Explanation:
Put into the proper order, the following are the stages of star formation from earliest to latest:
Massive, rotating, amorphous interstellar cloud collapses and fragments → Infalling material forms a hot and luminous protostar at the center of the disk → Gravitational contraction causes protostar to shrink and heat as it descends the Hyashi track → As the shrinking protostar heats up, hydrogen is ionized and a magnetic field forms → Magnetic bipolar outflows begin along rotation axis as the magnetic field forms → As bipolar outflows become stronger, powerful T-Tauri winds start clearing the nebula before the onset of nuclear fusion → Shrinking cloud collapses into a flat disk shape → Onset of nuclear fusion in the core occurs around 15 million K → Newly-formed star settles onto the Main Sequence
Answer:
Explanation:
30 rev/min (2π rad/rev) / (60 s/min) = π rad/s
α = Δω/t = (0 - π)/3 = π/3 rad/s²
θ = ½αt² = ½(π/3)3² = 1.5π radians
θ = 1.5π rad/2π rad/rev = 0.75 rev