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sweet-ann [11.9K]
3 years ago
5

When Earth’s Northern Hemisphere is tilted toward the Sun during June, some would argue that the cause of our seasons is that th

e Northern Hemisphere is physically closer to the Sun than the Southern Hemisphere, and this is the primary reason the Northern Hemisphere is warmer. What argument or line of evidence could contradict this idea?
Physics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

Distance of Earth from the Sun has nothing to do with the seasons only the tilt is responsible for the change in seasons.

Explanation:

The Earth's tilt does cause the seasons but the distance from the sun and has nothing to do with the change in seasons. In June, when the Northern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere summer the Earth is actually farthest from the Sun. In January, when the Southern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere winter the Earth is actually closest to the Sun. This is caused due to the elliptical orbit of the Earth. So, distance of Earth from the Sun has nothing to do with the seasons.

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A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d
Ivanshal [37]

Answer:

a)q= 2800 W/m²

b)To=59.4°C

Explanation:

Given that

L = 10 mm

K= 20 W/m·K

T=30°C

h= 100 W/m²K

Ti=58°C

a)

Heat flux q

q= h ΔT

q= 100 x (58 - 30 )

q= 2800 W/m²

b)

As we know that heat transfer by Fourier law given as

Q= K A ΔT/L

Lets take outer temperature is To

So by  Fourier law

To= Ti + qL/K

Now by putting the values

To= Ti + qL/K

To= 58 + 2800 \times \dfrac{ 0.01}{20}

To=59.4°C

5 0
3 years ago
A supersonic airplane is flying horizontally at a speed of 2650 km/h. What is the centripetal acceleration of the airplane, if i
Andrew [12]

Answer:

a_{c}=82617.65km/h^{2}\\  or\\a_{c}=6.37m/s^{2}

Explanation:

Given data

Speed v=2650 km/h

Radius r=85.0 km

To find

Centripetal Acceleration

Solution

As centripetal acceleration is given as

a_{c}=\frac{v^{2} }{r}................eq(i)

where

v is velocity

r is the radius

Substitute the given values in eq(i)

a_{c}=\frac{(2650km/h)^{2} }{85km} \\a_{c}=82617.65km/h^{2}\\  or\\a_{c}=6.37m/s^{2}

5 0
3 years ago
What is the attractive or repulsive force between two ferromagnetic objects is called?
Zanzabum
I am not sure the answers is correct

Magnetic Field, Magnetic Field, 1) When two magnets are brought near each other, like poles repel; opposite poles attract. ... We like to represent this force effect of a magnet on iron-like objects with a concept called magnetic field
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3 years ago
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The force (attractive if the charges are dissimilar, else repulsive) is along a line that connects the two particles.
3 0
3 years ago
The vector -B has a magnitude of 25 m and makes an angle of 30 degrees with the +x axis. Which is true about the vector B?
olga nikolaevna [1]

The given figure shows the arrangement of vectors

-B is acting with a magnitude of 25 with 30^0 to +X axis

So vector B is along the opposite direction of vector -B

Statement A is wrong since the direction is opposite

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Statement C is correct since it has 25 m magnitude

Statement D is wrong because vector's magnitude cannot be negative.

So option C is the correct answer.

7 0
3 years ago
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