Answer: 8Ω
Explanation:
Since there are two resistors of 4Ω
connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 4Ω
R2 = 4Ω
Rtotal = ?
Rtotal = 4Ω + 4Ω
Rtotal = 8Ω
Thus, the total resistance of the circuit is 8Ω
<h3>
Answer:</h3>
1.3 Amps
<h3>
Explanation:</h3>
<u>We are given;</u>
A circuit with resistors, R1 and R2
R1 = 7 Ω
R2 = 11 Ω
Voltage = 24 V
We are required to calculate the current in the circuit.
<h3>Step 1: We need to find the effective resistance.</h3>
When resistors are arranged in series, the effective resistance is calculated by;
Rt = R₁ + R₂ + R₃ + ..........Rₙ
Therefore;
Total resistance = 7 + 11
= 18 Ω
<h3>Step 2: Calculate the current in the circuit</h3>
From the ohm's law;
V = IR
Rearranging the formula;
I = V/R
Thus;
I = 24 V ÷ 18 Ω
= 1.333 Amps
= 1.3 Amps
Thus, the current in the circuit is 1.3 Amps
number 2 because the curve demstrates the crest GOOD LUCK i hope i got you the correct answer if not sorry
Explanation:
12N by first law of newton is net force after colloision
