<h3>
Answer:</h3>
f(x) = -(x -2)² +3
<h3>
Step-by-step explanation:</h3>
We can fill in the vertex (h, k) values immediately in the vertex form ...
... f(x) = a(x -h)² +k
To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:
... -1 = a(0 -2)² +3
... -4 = 4a . . . . . . . . . subtract 3, simplify
... -1 = a . . . . . . . . . . . divide by 4
Now, we know the function is ...
... f(x) = -(x -2)² +3
Answer:
See below.
Step-by-step explanation:
So, we have:
Recall that secant is simply the reciprocal of cosine. So we can:
Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
Which one do you need help on
0.0641 this is the answer
Answer:
89 2 irrational roots
Step-by-step explanation:
The discriminant Is b²-4ac when the equation is in the form
ax²+bx+c so in the equation
a=2 b=5 and c=-8
plug into the equation for the discriminant
so 5²-4(2)(-8)
25-(-64) 2 negatives make a positive so
25+64=89
since 89 isn’t a perfect square 2 irrational roots
