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malfutka [58]
4 years ago
15

mr. Choi spent $23 at the mall. If he left the mall with $59, how much money did he have when he first arrived at the mall?

Mathematics
1 answer:
Temka [501]4 years ago
8 0

Answer: 82

Step-by-step explanation:

59+23=82

Check

82-23=59

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The Taylors plan to expand their
podryga [215]

Answer:

A_{2} = 720\ ft^{2}

Step-by-step explanation:

Let w and l be the width and length of the garage.

Let A_{1} and A_{2} be the area of garage at present and new garage.

Given:

The area of the garage at present

A_{1}=80\ ft^{2}

And he planed to tripling the dimensions of the garage.

We need to find the area of the new garage.

Solution:

We know the area of the rectangular garage.

Area=width\times lendth

A_{1}=w\times l

w\times l=80 ---------------(1)

The dimension of the new garage is triple, so the area of the new garage is.

A_{2} = (3\times width)\times (3\times length)

A_{2} = (3\times w)\times (3\times l)

A_{2} = 9\times (w\times l)

Substitute w\times l=80 from equation 1.

A_{2} = 9\times (80)

A_{2} = 720\ ft^{2}

Therefore, the area of the new garage A_{2} = 720\ ft^{2}

4 0
4 years ago
Can someone answer this for me ill give brainliest asap
Valentin [98]
The answer is non linear
6 0
3 years ago
Which two values of x are roots of the polynomial? x^2-11+15
devlian [24]
Add -11 and 15 to get 4
x^2 + 4
7 0
4 years ago
Pls help pls ill give u a braniest if you help me
alexandr1967 [171]

Answer:

B

Step-by-step explanation:

y = (x + 1)/x

xy = x + 1

xy - x = 1

x(y - 1) = 1

x = 1/(y - 1)

Interswitch variables

f^-1(x) = 1/(x - 1)

4 0
4 years ago
angle 1 and angle 2 are vertical angles. if the measure of angle 1 is (6x+11)° and measure of angle 2 is (10x-9)° find measure o
Svetradugi [14.3K]

Answer:

Angle 1 = 41°

Step-by-step explanation:

Since they are both vertical angles

(6x+11)° = (10x-9)°

6x - 10x = -9 - 11

-4x = -20

4x = 20

x= 5.

Therefore,

Angle 1 = 6(5) + 11

Angle 1 = 30 + 11

Angle 1 = 41°

5 0
3 years ago
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