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Fittoniya [83]
3 years ago
13

A picture could hold to 12th of a gallon of water if Roger filled up nine pictures how much water would he have

Mathematics
1 answer:
TEA [102]3 years ago
8 0

Answer:

He would have a very soggy picture!

OR if you mean the pitcher holds one twelvth of a gallon, he will have 9/12 or 3/4 of a gallon.

OR if you mean the pitcher holds two twelvths of a gallon, he ends up with 9 × 1/6 which is one and a half gallons.

Step-by-step explanation:

Spelling is important! A "picture" could be a drawing, a photograph, or a painting.

"Pitcher" could be a container for pouring liquids or a player who pitches the ball in a baseball game.

I know you wanted math help, but it is difficult to answer if I can't tell whether "to" meant "two" or he filled the pitcher to pour twelvths.

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Answer: c

Step-by-step explanation:

7 0
3 years ago
3x-7&gt;5<br> Find the solution, please show your work. Thank You!1
miskamm [114]
To find x just change the <span>> to a =
</span><span>3x-7=5
add 7
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then divide by 3
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7 0
3 years ago
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Musya8 [376]

Answer:

B, The initial number of bacteria increases at a rate of 24% each day.

Step-by-step explanation:

I think the answer is B because it is the one that closely matches the problem. 312 is multiplied by 1.24 with an exponent. Just eyeballing it, it's multiplied by itself and then an increase of 24%. Also, none of the other statements seem to be correct, D not even making sense in the scope of the problem. Hope this helps, good luck.

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3 years ago
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9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of
netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12, \sigma = 3

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 12}{3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

1 - 0.9082 = 0.0918

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0
3 years ago
Can anyone answer this question please<br> 6[y-2]/7-12=2[y-7]/3
Kaylis [27]

Answer:

y =47.5.

Step-by-step explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

18(y - 2) - 252 = 14(y - 7)

18y -36 - 252 = 14y - 98

18y - 14y = -98 + 36 + 252

4y = 190

y = 190/4

y = 47.5.

8 0
2 years ago
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