A example can be Keith has $500 in a savings account at the beginning of the summer. He wants to have at least $200 in the account by the end of the summer. He withdraws $25 each week for food, clothes, and movie tickets. The answer would be Any more than 12 weeks and his account balance would be less than $200. Any number of weeks less than 12 and his account would stay above $200.
Answer:
Two times at (-1,0) and (2.5,0)
Step-by-step explanation:
When the graph intersects or touches x-axis, y is equal to 0
so y = -2x^2 + 3x + 5
=> 0 = -2x^2 + 3x + 5
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
so a = -2
b = 3
c = 5
substitute in the formula
x = [-3 +/- √(3^2 - 4x-2x5)]/2(-2)
x = [-3 +/- √(9 + 40)]/(-4)
x = [-3 +/- 7]/(-4)
x1 = (-3 + 7)/(-4) = 4/-4 = -1
x2 = (-3 - 7)/(-4) = -10/-4 = 5/2 = 2.5
so the graph has two x-intercepts (-1,0) and (2.5,0), therefore it intersects x-axis two times
a) 20(x)=y
b) $120
Let x= number of hours
Let y= Cost of labor
20 will remain constant, what matters is how many hours are being worked. If it's $20 per hour then it's safe to assume 1 hour is 20 dollars worth of labor. Due to it being per hour you have to multiply the rate by however many hours worked to get your final cost.
Find the difference then put it over (divide it from) the original.
