Answer:
One cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.
Step-by-step explanation:
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
Answer:
x= 16±√-64 over 2
Step-by-step explanation:
x= -(-16)±√(-16)²-4×1×80 over 2×1
x= 16±√256-320 over 2
x= 16±√-64 over 2
can also be represented with all real numbers.
Answer:
<u><em>y' = 1 / sinxcosx</em></u>
Step-by-step explanation:
<u>Given :</u>
y = sinx + cosx / sinx - cosx
<u>Applying quotient rule :</u>
y' = [(sinx - cosx)(cosx - sinx) - (sinx + cosx)(cosx + sinx)] / (sinx -
cosx)²
y' = [sinxcosx - cos²x - sin²x + sinxcosx - (sinxcosx + cos²x + sin²x + sinxcosx)] / (sinx - cosx)²
y' = 2sinxcosx - 2sinxcosx - 2cos²x - 2sin²x / (sinx -cosx)²
y' = -2(sin²x + cos²x) / (sinx - cosx)²
y' = -2 / (sinx - cosx)²
y' = -2 / sin²x - 2sinxcosx + cos²x
y' = -2 / -2sinxcosx
<u><em>y' = 1 / sinxcosx</em></u> [⇒ Final answer]
Heres the answer you’re looking for.
y= -2x-4