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FinnZ [79.3K]
4 years ago
13

Which best describes the data set?

Mathematics
2 answers:
MAXImum [283]4 years ago
4 0

Answer:

The answer is C

Step-by-step explanation:

It is nonlinear but you have to look at it compared to the months passed. In three months the total houses built are 33 this would mean each month they build 11 houses but in the fourth month they have built 46 houses because 46-11 dosnt equal 33 it is nonlinear.

Romashka-Z-Leto [24]4 years ago
4 0

Answer:  It is nonlinear because the increase in the "Total house built" compared to the "Months Passed" does not show a constant rate of change.

Step-by-step explanation:

We say function to be linear if the rate of change in dependent variable (y) with respect to independent variable (x) is constant.

Rate of change =\dfrac{\text{Change in dependent variable}}{\text{Change in independent variable}}

According to the question ,

Independent variable = Number of months

Dependent variable = Total house built

Now rate of change of "Total house built" for month 0 to 3:-

\dfrac{33-0}{3-0}=\dfrac{33}{3}=11                           (1)

Rate of change of "Total house built"fro month 3 to 4:-

\dfrac{46-33}{4-3}=\dfrac{13}{1}=13                         (2)

From (1) and (2), it is clear that the rate of change is not constant

(∵ 11≠ 13 ).

Hence, the correct answer is : It is nonlinear because the increase in the "Total house built" compared to the "Months Passed" does not show a constant rate of change.

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URGENT: statistics: A researcher wishes to estimate the percentage of adults who support abolishing the penny what size sample s
irina1246 [14]

Using the margin of error for the z-distribution, the sample sizes are given as follows:

a) 822.

b) 1068.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

We have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Item a:

The estimate is of \pi = 0.26, hence we solve for n when M = 0.03.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.26(0.74)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.26(0.74)}

\sqrt{n} = \frac{1.96\sqrt{0.26(0.74)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.26(0.74)}}{0.03}\right)^2

n = 821.2

A sample of 822 is needed.

Item b:

No prior estimate, hence \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1067.11

A sample of 1068 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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