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2 years ago

How do you find the median

2 answers:

4 0

In a list of numbers, such as 1,2,3,4,5,6,7, start from the right and cross off the last number. In this case, it's the 7. Then, go to the left and cross of the first number, the one. Keep going from right to left, and when you get down to one number in the middle, that is the median. However if there are two numbers in the middle, I think that you have to find the mean of those two numbers, and that should be the median. That's only if there are two numbers left in the middle. Hope this helps!

damaskus [11]2 years ago

4 0

The median is the middle score for a set of data that has been arranged in order of magnitude.

So order your vales, and then pick the middle record.

This works fine when you have an odd number of scores.

BUT

What happens when you have an even number of scores?

It is easy...

You would calculate the mean of the two middle records ..

in other words:
you simply have to add up the middle two scores and average the result.

I hope that helps!

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I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)

LiRa [457]

Let's set it up like this:
$0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}$
Multiply both sides by $0.05-x$
$0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)$
$0.513\left(0.05-x\right)=4x^2$
We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
$x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}$
The variable $x$ can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

4 0

3 years ago

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

2 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago

a rectangle prism has a volume of 3x^2 + 18x+ 24. its base has a length of x + 2 and width of 3, what expression represents the

OlgaM077 [116]

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\qquad 
\begin{cases}
l=x+2\\
w=3\\
V=3x^2 + 18x+ 24
\end{cases}\implies \cfrac{V}{lw}=h
\\\\\\
\cfrac{3x^2 + 18x+ 24}{3(x+2)}=h\implies \cfrac{\underline{3}(x^2 + 6x+ 8)}{\underline{3}(x+2)}=h
\\\\\\
\cfrac{(x+4)\underline{(x+2)}}{\underline{(x+2)}}=h\implies x+4=h$

6 0

3 years ago

An employee earned $3,300 working for an employer in the current year. the current rate for fica social security is 6.2% payable

spin [16.1K]

Employer's Total FICA Tax = $3,300 * (0.062 + 0.0145) = $252.45

7 0

3 years ago