Since m∠JOK is 1/5th of the measure of the full circle (we know this because 72° is 1/5th of 360° and 360° is the measure of the whole circle), we know that the measure of minor arc JK will be 1/5th of the circumference of the circle. C = 2πr and we know that r = 5 so the circumference is 10π. 1/5th of that is 2π.
Y=3(x+1)(x-5) I'm going to ignore 3 for now, but will add it later. FOIL the (x+1)(x-5) F = multiply the First numbers x and x O = multiply the Outside numbers x and -5 I = multiply the Inside number 1 and x L = multiply the Last numbers 1 and -5 3(x^2 + -5x + 1x + -5) add -5x and x 3(x^2 + -4x + -5) multiply the numbers inside the parenthesis by 3 3x^2 + -12x + -15