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salantis [7]
3 years ago
7

Match the chart to the type:

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Solution :

1. A chart monitoring the object counts with some specific characteristic during the time period and/or some of consistent amount area -- c. c - chart

2. A chart which monitors the subgroup variations within the range of subgroups -- a. R chart

3. The chart monitoring the variation of within subgroup to that of the standard deviations of the subgroups -- d. s chart

4. The chart which monitors the objects' proportion from the sample size of n which does or does not have any particular characteristics -- g. p chart

5. The chart monitoring the averages between the subgroup of the quantitative characteristic keys -- b. x-"bar" chart

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-7y^2+3y-6y-(3y^2+4y+4)
patriot [66]

Answer:

-10y^2-7y-4

Hope this helps!

3 0
2 years ago
Read 2 more answers
Solutions to 2-variable equations y=-2x-5
vodomira [7]

Answer:(1, -3).

Step-by-step explanation:

If y=2x-5 is equation (1) and 4x-y=7 is equation (2), then substitute equation (1) in equation (2):

4x - (2x - 5) = 7

4x - 2x + 5 = 7

2x = 7-5

2x = 2

x = 1

Now substitute the value of x in equation (1) to find the value of y:

y = 2 (1) - 5

y = 2 - 5

y = -3

3 0
3 years ago
How many yards are equal to 240 feet
HACTEHA [7]
80 yards equal 240 feet
You have to divide 240 by 3 since there are 3 feet in a yard
8 0
3 years ago
find the number of subsets of s = 1 2 3 . . . 10 that contain exactly 4 elements including 3 or 4 but not both.
Anna007 [38]

Answer:

112

Step-by-step explanation:

Let A be a subset of S that satisfies such condition.

If 3∈A, then the other three elements of A must be chosen from the set B={1,2,5,6,7,8,9,10} (because 3 cannot be chosen again and 4 can't be alongside 3). B has eight elements, then there are \binom{8}{3}=56 ways to select the remaining elements of A (the binomial coefficient counts this). The remaining elements determine A uniquely, then there are 56 subsets A.

If 4∉A, we have to choose the remaining elements of A from the set B={1,2,5,6,7,8,9,10}. B has eight elements, then there are \binom{8}{3}=56 ways to select the remaining elements of A. Thus, there are 56 choices for A.

By the sum rule, the total number of subsets is 56+56=112

4 0
4 years ago
Please please please help
SVETLANKA909090 [29]

Answer: ah yes of course 5 head

Step-by-step explanation:

lol

4 0
4 years ago
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