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3 years ago

8

Find the equation of the line that passes throught the points A and B. A- (1, 7)B- (-3, -1)

1 answer:

scoray [572]3 years ago

6 0

Answer:

y=2x+4

Step-by-step explanation:

check the gradient first

find the y intercept

fill it

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Please help me simplify 4^8/4^5

Oksi-84 [34.3K]

Answer:

64

Step-by-step explanation:

64

Hope it helped!

4 0

3 years ago

Read 2 more answers

V125BC [204]

Answer: 7 π r² + π r³

Explanation:

1) The general formula for the volumen, V, of a cylinder with radius r and height h is:

V = π r² h

2) Now you have the condition that the height is 7 inches greater than the radius, that is:

h = 7 + r

3) Replace h with its expression

V = π r² (7 + r)

4) Expand the product (use distributive property):

V = π (7r²) + π r³ = 7 π r² + π r³

Answer: 7 π r² + π r³

3 0

3 years ago

The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway

marysya [2.9K]

Answer:

The coordinate of the rest stop is: $(5,2.5)$

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

$(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

This gives:

$(x,y) = \frac{1}{2}(3+7,4+1)$

$(x,y) = \frac{1}{2}(10,5)$

Open bracket

$(x,y) = (5,2.5)$

Solving (b): Distance between the hotel and the stadium

We have:

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

The distance (d) is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$d = \sqrt{(3 - 7)^2 + (4 - 1)^2}$

$d = \sqrt{(-4)^2 + 3^2}$

$d = \sqrt{16 + 9}$

$d = \sqrt{25}$

$d =5$

From the question, we have:

$1\ unit = 6.4\ miles$

So:

$d =5 * 6.4\ miles$

$d =32\ miles$

3 0

3 years ago

What are the X and Y intercepts of y= -2(x-4)2 +3

kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

$y = -2(x-4)^2+3$

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, $-2(x-4)^2 + 3 = 0$

$-2(x^2+16+8x) + 3 = 0$

$-2x^2-32-16x + 3 = 0$

$-2x^2-16x -29 = 0$

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)

4 0

4 years ago

Find the sum and express it in the simplest form (-2y-4x+7)+(-4y+x-1)

Marina86 [1]

Y=7+2x......(1)

put this value in 4y+x=1

4(7+2x)+x=1

28+14x+x=1

15x=-27

x=-27/15.....(2)

put this value in eqn (1)

y=7+2(-27/5)

y=7-54/5

y=-3.8

I really hope this helps :D:D:D!!!!

3 0

3 years ago

Read 2 more answers