All categories

2 years ago

If m<13=m<15=m<7, what conclusions can you make about lines a, b, c, and d?

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

5 0

Answer:

option D

Lines a and b are parallel and lines c and d are parallel.

Step-by-step explanation:

Given in the question four lines a , b, c, d.

<h3>Prove one</h3>

If two parallel lines (a,b) are cut by a transversal(d), then corresponding angles m<7 and m<15 are congruent.

They are know as corresponding angles.

Hence lines a and b are parallel.

<h3>Prove two</h3>

If two parallel lines (c,d) are cut by a transversal(d), then corresponding angles m<13 and m<13 are congruent.

They are know as corresponding angles

Hence lines c and d are parallel

You might be interested in

What is the definition of a change in position or size?

Troyanec [42]

Transformation.. If you're referring to geometry

7 0

3 years ago

there are 12 boys and 10 girls in the gym class. If 6 more boys joined , how many more girls are needed to stay at the same rati

Travka [436]

Hope this helps good luck ☺

4 0

3 years ago

Gcantiga44 Help please. I need help.

Hunter-Best [27]

1st scenario - 0.82x

2nd scenario - 1.18x

3rd scenario - 3/10x

4th scenario - 13/10x

7 0

3 years ago

Read 2 more answers

Tell which transformation is shown by the change in ordered pairs

iren [92.7K]

Answer:

Translation

Step-by-step explanation:

Transformation is the movement of objects in the coordinate plane. It can be through any of translation, reflection or rotation. The kind of transformation that occurs in ordered pairs is translation e.g if the ordered pair is (1, 4) x = 1, while y = 4. if it is translated we have (4, 1) such that x is now 4 while y is 1

4 0

3 years ago

Which of the following functions are solutions of the differential equation y+4y+4y=0? A. y(x) =e^-2x B. y(x) = e^+22 C. y(x) =

zmey [24]

Answer: E. y(x) = 0

Step-by-step explanation:

y(x) = 0 is the only answer from the options that satisfies the differential equal y" - 4y' + 4y = 0

See:

Suppose y = e^(-2x)

Differentiate y once to have

y' = -2e^(-2x)

Differentiate the 2nd time to have

y" = 4e^(-2x)

Now substitute the values of y, y', and y" into the give differential equation, we have

4e^(-2x) - 4[-2e^(-2x)] + 4e^(-2x)

= 4e^(-2x) + 8e^(-2x) + 4e^(-2x)

= 16e^(-2x)

≠ 0

Whereas we need a solution that makes the differential equation to be equal to 0.

If you test for the remaining results, the only one that gives 0 is 0 itself, and that makes it the only possible solution from the options.

It is worth mentioning that apart from the trivial solution, 0, there is a nontrivial solution, but isn't required here.

7 0

3 years ago