Consider rectangular box with
- length x units (x≥0);
- width 3 units;
- height (8-x) units (8-x≥0, then x≤8).
The volume of the rectangular box can be calculated as

In your case,

Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).
From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.
Then the volume will be V=0 (minimal).
Answer: correct choices are B (the maximum possible length), C (the minimum possible height)
The center of the circle is f(6,10)
Answer:
y = 3
Step-by-step explanation:
2x-3y = -5 --------- (1)
y = 2+x ------- (2)
substitute (2) into (1)
2x-3y = -5
2x-3( 2+x ) = -5
2x-6-x = -5
2x-x = -5+6
x = 1
substitute x = 1 into (2)
y = 2+x
y = 2+1
y = 3
What about it? Specify please.
Answer:
I think it B as well as the other person I just learned this so I'm not the best at it