A device used to initiate and control a sustained nuclear chain reaction.
It's not. It's equivalent to the transfer of that many elementary charges <u>every second</u> .
The elementary charge (charge on an electron) is
1.60 x 10⁻¹⁹ coulomb / electron.
The number of electrons in a Coulomb is the reciprocal of that number.
6.25 x 10⁻¹⁸ electrons / Coulomb.
There's the number. 1 Coulomb <em>per second</em> is called 1 Ampere.
Answer:
the volume that has 1.0m^2 of water from the surface of the lake is 4.3
Explanation:
The computation of the volume is as follows;
The Bulk modulus is
= K = 2.3 × 10^9 Pa
K = - V dP ÷ dV
dV = - V dP ÷ K
dV = - (1 × 101.3 × 1000) ÷ 2.3 × 10^9
= - 4.3 × 10^-3 m^3
So the volume that has 1.0m^2 of water from the surface of the lake is 4.3
Hence the same is relevant and considered
Answer:
The first questions answer is letter A
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
= K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v =
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ =
Let's calculate
μ =
μ = 0.125