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ad-work [718]
3 years ago
10

Which one of the following temperatures is equal to 5°C?

Physics
1 answer:
natali 33 [55]3 years ago
7 0

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature 5^oC.

Now the conversion factor used for the temperature is,

K=^oC+273

where, K is kelvin and ^oC is Celsius.

Now put the value of temperature, we get

K=5^oC+273=278K

Therefore, the temperature 278 K is equal to the 5^oC


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Match each description to its written source.
madreJ [45]
1=6, 2=8
I hope this helped

3 0
4 years ago
1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?​
DIA [1.3K]

Answer:

5 m/s is the answer so yeah

5 0
3 years ago
Un objeto que es empujado sobre una superficie plana, tiene una masa de 80 kg y dicha fuerza tiene un valor de 300 N. Calcule la
Gennadij [26K]

Responder:

A. Ff = 300 N N = 784,8 N

Explicación:

Dado

Masa del cuerpo = 80 kg

Fuerza de movimiento Fm = 300N

Dado que el cuerpo no está acelerando, la fuerza de fricción (Ff) es igual a la fuerza de movimiento que actúa sobre el cuerpo, ya que la fuerza de fricción es una fuerza de oposición, es decir, Fm = Ff

Dado que Fm = 300N, Ff = 300N

La reacción normal que actúa en el cuerpo es igual al peso.

N = W = mg

g es la aceleración debida a la gravedad

g = 9,8 m / s

N = mg

N = 80 (9,81)

N = 784,8N

Por tanto, la fuerza normal que actúa sobre el cuerpo es 784,8 N

3 0
3 years ago
the natural radioactivity is done by(controlling the nuclear energy-no ability to control the nuclear energy-both of them)​
just olya [345]

Answer:

Nuclear power plants are fueled by uranium, which emits radioactive substances. Most of these substances are trapped in uranium fuel pellets or in sealed metal fuel rods. However, small amounts of these radioactive substances (mostly gases) become mixed with the water that is used to cool the reactor.

5 0
3 years ago
El vector a tiene componented ax= 2.70 cm, ay=2.25 cm; y el vector b tiene componentes bx= 0.30 cm, by= 1.75 cm. Calcular las co
Talja [164]

Answer:

Explanation:

Given that,

A vector A has x component to be 2.7cm and y component to be 2.25cm

Then,

A = 2.7•i + 2.25•j

A vector B has x component of 0.30cm and y component of 1.75cm

B = 0.3•i + 1.75•j

So, we want to find A+B

Addition of vectors

Generally

(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j

Vectors are added component wise.

So,

A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)

A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j

A + B = 3•i + 4•j

We can also find it magnitude and direction

Generally,

A = a•i + b•j

|A| = √(a²+b²)

<A = arctan(b/a)

So,

|A+B| = √(3²+4²) = √9+16 = √25

|A+B| = 5

And it's direction

< = arctan(y/x)

< = arctan(4/3)

< = 53.13°

3 0
3 years ago
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