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3 years ago

15

the table below shows the account balances for four different customer accounts at the city bank.which account balance represent

s a debt that is greater than $20 and less than $30?

2 answers:

Sonbull [250]3 years ago

6 0

Answer:

ARE THERE ANY ANSWER CHOICES?

Step-by-step explanation:

Iteru [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

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How many gallons of a 70% antifreeze solution must be mixed with 60 gallons of 20% antifreeze to get a mixture that is 60% a

Flura [38]

We have 60 gallons of 20% antifreeze.

How much 70% antifreeze do we add to get 60% antifreeze?

We'll make "x" the gallons of 70% we must add.

.20 * 60 + .70 x = .60 * (60 + x)

12 + .70x = 36 + .60x

.10x = 24

x = 240 gallons of 70% antifreeze.

Source

1728.com/mixture.htm (see example B)

4 0

2 years ago

Dan was thinking of a number. Dan doubles it and gets an answer of 34.7. What was the original number?

Ksju [112]

347/2 just did it!!! Good luck

3 0

2 years ago

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Write a rule for the function whose graph can be obtained from the given parent function by performing the given transformations

kati45 [8]

ANSWER

$g(x) = {(x + 5)}^{3} + 4$

EXPLANATION

Given the parent function:

$f(x) = {x}^{3}$

If we shift the graph of f(x), 5 units to the left, then the new rule is

$x \to \: {(x + 5)}^{3}$

If we again, shift this graph upward by 4 units, then the completely transformed function will have the rule,

$x \to \: {(x + 5)}^{3} + 4$

Or

$g(x) = {(x + 5)}^{3} + 4$

7 0

2 years ago

Using addition formula solve tan 15

salantis [7]

Answer:

2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = $\frac{tanA-tanB}{1+tanAtanB}$ and the exact values

tan45° = 1 , tan60° = $\sqrt{3}$ , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

= $\frac{\sqrt{3}-1 }{1+\sqrt{3} }$

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

= 2 - $\sqrt{3}$

3 0

2 years ago

How to use denominators when comparing two fractions with the same numerators

Sholpan [36]

What you would do is take the denominators and multiply them by each other, then multiply the numerators by that same number. So like 4/10 and 4/9. You would say, (denominators) 10x9=90 and (numerators) 4x9=36. So your first fraction would be 36/90. Next, you would take (denominators) 9x10=90 and (numerators) 4x10=40. So your second fraction would become 40/90. Now it's a lot easier to compare. 36/90 < 40/90 would be the answer to my problem. I hope I helped!

4 0

3 years ago

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